UnboundLocalError:局部变量' n'在分配之前引用

时间:2015-10-23 22:04:05

标签: python dice

我在代码底部添加if语句后出现此错误:

  

UnboundLocalError:局部变量' n'在分配前引用

任何想法有什么不对?

import random

n=input('Write number of spaces you want to be playing on: ')
if n < 3:    
    print "Gotta be more than 3 mate"
    a = input('Would you like to end the program and try again?')
    exit()
else:    
    print"You're playing on %d lines" % n

def DieGame(dieSize,numberDie):   # dieSize (6 sides = 6),number of die (in this case,it'll be one
    result = 0
    value = 0
    rounds = 1

    while n > 1:
        print "Round number " ,rounds

        for i in range(0,numberDie):         # starting at 0 , number of die
            result = random.randint(1,dieSize)  #random number, 1 - size of dice(6 in this case)
            print("On %d dice/die,you've rolled %d." % (i+1,result))  
            value += result

        print("Value of the roll/s %d of the dice/die is: %d" % (numberDie,value))

        if (n - value) > 1:     #if I'll get anything else than 1,its okay
            print "New position: " ,n-value
        if n == 1:
            print "You've reached 1 space right before the finish,return back by 1."
            n += 1                   
        if (n-value) == 0:

            a = input('Congratulations, you made it to the end! Press Enter to close the game.')
            exit()

        rounds += 1
    else:
        print "End"
    DieGame(6,1)
#-------------------------------------------------------
#Gotta break the loop once I get to 0,or If I was to cross 0 to -1 and less.Can't cross 0.

#If I'll be like 4 spaces from finish and I'll roll 6,I wont be able to move,gotta reach the last space.

#Gotta make it reroll if I roll 1,add rolls to sum and then move forward by that number
#if rolled for example 1+1+1(rerolling) + 3,add the sum together and move by 6.   

#if you step on the last space before the finish ,get one space back

1 个答案:

答案 0 :(得分:0)

您的问题是在函数外部分配了%s/\v\w(\.\d|$)@!/&, /g 。这会导致问题:

a, b, c, d, e
1, 2, 3, 4, 5
1.5, 2, 3.5, 4, 5.5

鉴于:

n

需要在那里定义在特定词法范围内使用的变量。如果闭包不包含>>> n = 3 >>> def x(): ... while n > 1: ... print("Iterating. n={}".format(n)) ... n = n - 1 ... >>> x() Traceback (most recent call last): File "<stdin>", line 1, in <module> File "<stdin>", line 2, in x UnboundLocalError: local variable 'n' referenced before assignment ,则尝试引用它会导致问题。