如果不满足要求，Jquery重复ajax调用

Question

好吧所以我想要的是在按下按钮后开始循环ajax调用，ajax将与数据库进行通信，并根据响应，我希望它循环，并重新执行完全相同的调用，或者停止呼叫并转到另一个功能。

我现在有以下代码：

     function checkResult(session, ip, key){
    $.ajax({
        url: "myUrl"+key,
    }).success(function(returnData){
        returnData = returnData.replace("\n", "");
        returnData = returnData.replace(" ", "");
        if(returnData == 1){//Everything is fine, stop the call
            clearInterval(interval);
            console.log("completed");
        }else if(returnData == 2){//Something went wrong, stop the call
            clearInterval(interval);
            console.log("Something went wrong");
        }else if(returnData == 0){//No result found, repeat call
            console.log("Nothing was found");
            return returnData;
        }
    });
}

function repeatCall(session, ip, key){
    console.log("Repeating the request");
    interval = setInterval(function(){ var status = checkPayment(session, ip, key); if(status != 0){
        clearInterval(interval);
        checkResult(status)}}, 1000);
}

它目前仅循环整个调用一次，它在我的控制台中记录“未找到任何内容”。让这个工作的正确方法是什么？

Answer 1

呃，如果我理解你的话，你应该可以做这样的事情......

function makeAJAXRequest(session, ip, key)
{
    $.ajax({
        type:'POST', // or GET
        url: "myUrl"+key,
        success: function(status){
            returnData = returnData.replace("\n", "");
            returnData = returnData.replace(" ", "");

            if(returnData == 1)
            {   //Everything is fine, stop the call
                clearInterval(interval);
                console.log("completed");
            }
            else if(returnData == 2)
            {   //Something went wrong, stop the call
                clearInterval(interval);
                console.log("Something went wrong");
            }
            else if(returnData == 0)
            {   //No result found, repeat call
                console.log("Nothing was found");
                makeAJAXRequest(session, ip, key);
            }
        },
        error: function(status, err){
            // dome something
        }
    });
}