Question

此问题似乎难以复制 - 因为我能够在较短的程序中正确执行此操作。我希望的是可能出现问题的一些指导。我已经发布了它正常工作的版本：

import tkinter as tk
from tkinter import *
from tkinter import ttk

class DIS(tk.Tk):

    def __init__(self, *args, **kwargs):

        tk.Tk.__init__(self, *args, **kwargs)
        tk.Tk.wm_title(self, "program")
        container = tk.Frame(self)
        container.pack(side="top", fill="both", expand = True)
        container.grid_rowconfigure(0, weight = 1)
        container.grid_columnconfigure(0, weight = 1)
        self.usernameVar = StringVar()
        self.frames = {}
        for F in (StartPage, contactQues, nowTry, next):
            frame = F(container, self)
            self.frames[F] = frame
            frame.grid(row = 0, column = 0, sticky = "nsew")
            self.show_frame(StartPage)

    def show_frame(self, cont):
        frame = self.frames[cont]
        frame.tkraise()


class StartPage(tk.Frame):
    def __init__(self, parent, controller):
        tk.Frame.__init__(self, parent)

        button2 = ttk.Button(self, text = "Here's a Button", command= lambda: controller.show_frame(nowTry))
        button2.pack()


class nowTry(tk.Frame):
    def __init__(self, parent, controller):
        tk.Frame.__init__(self, parent)
        self.controller = controller

        self.entry1 = Entry(self)
        self.entry1.pack()

        self.button1 = ttk.Button(self, text = "Yes", command = self.go)
        self.button1.pack()

        self.entry1.bind("<Return>", self.go)

    def go(self, event=None):
        print (self.entry1.get())
        self.controller.show_frame(contactQues)


class contactQues(tk.Frame):
    def __init__(self, parent, controller):
        tk.Frame.__init__(self, parent)
        self.controller = controller

        self.entry1 = Entry(self)
        self.entry1.pack(pady=10, padx=10)


        self.button1 = ttk.Button(self, text = "Submit", command= self.UsernameSubmit)
        self.button1.pack()

        self.entry1.bind("<Return>", self.UsernameSubmit)

    def UsernameSubmit(self, event=None):
        UsernameEntryGet = self.entry1.get()
        self.controller.usernameVar.set(UsernameEntryGet)
        self.controller.show_frame(next)


class next(tk.Frame):
    def __init__(self, parent, controller):
        tk.Frame.__init__(self, parent)
        self.controller = controller

        label = tk.Label(self, textvariable = self.controller.usernameVar)
        label.pack() ###Label is posted with input correctly

我在主程序中遇到的问题是self.controller.usernameVar标签在按下Return键提交时，不会像在此示例中那样发布（根本没有显示）输入。但是，当用鼠标单击submit按钮时，标签会正确显示。

因此，根据这些信息，我觉得我的bind("<Enter>"...命令管理错误。我已尝试self.bind...，self.controller.bind...，self.entryX.bind...但未成功。

这个框架的任何想法都可能出错？

Answer 1

我相信我明白了。问题是，在我的完整程序中，我有多个bind命令。在我尝试解决此问题时，我有一些entry提示绑定到controller，其他提示绑定到entry本身（例如，self.controller.bind在几个类中其他人self.entry.bind。

我将它们全部更改为self.entry.bind并且显然已修复它 - 这就是为什么此代码段按预期工作的原因。

Tkinter绑定不一致

1 个答案: