所以我有一个测试从列表中删除了一些项目(最终删除了所有项目):
for (int i=1; i<=150;i++) {
String id = "T" + i;
Iterator<Item> iter6 = tree.find(id);
if (iter6.hasNext()) {
Item item = iter6.next();
tree.remove(id, item);
}
}
Iterator<Item> all6 = tree.listAll();
int counter6 = 0;
while(all6.hasNext()) {
counter6++;
all6.next();
}
if (counter6==0) {
System.out.println("TEST 6 pass");
} else {
System.out.println("TEST 6 fail");
}
注意:是的我100%确定树中有150个项目:)
这是我的remove方法,从树中删除一个节点,然后重新平衡树:
public class AVLTree<K, V> implements IAVLTree<K, V>
{
public class Node {
private K key;
private ArrayList<V> valuesList;
private Node left, right;
private int height;
public Node(K key, ArrayList<V> valuesList) {
this.key = key;
this.valuesList = valuesList;
this.height = 0;
}
public Node(V value) {
}
public void addToNode(V value) {
valuesList.add(value);
}
public K getKey() {
return key;
}
public ArrayList<V> getValues() {
return valuesList;
}
public Node getChildNodeFromSide(String side) {
switch(side) {
default: return null;
case "left": return left;
case "right": return right;
}
}
}
private Node rootNode;
private Comparator<K> comparator;
//Unused
public AVLTree() {
}
public AVLTree(Comparator<K> comparator) {
this.comparator = comparator;
this.rootNode = null;
}
@Override
public V remove(K key, V value) throws Exception {
remove(key, value, rootNode);
return value;
}
private Node remove(K key, V value, Node node) {
//If node with key contains one or less values, remove the whole key
//Else remove value from node with key
if(node == null) return null;
else if(comparator.compare(key, node.key) < 0) {
node.left = remove(key, value, node.left);
if(height(node.left) - height(node.right) == 2) {
if(comparator.compare(key, node.left.key) < 0)
node = rotateWithLeftChild(node);
else
node = doubleRotateWithLeft(node);
}
} else if(comparator.compare(key, node.key) > 0) {
node.right = remove(key, value, node.right);
if(height(node.right) - height(node.left) == 2) {
if(comparator.compare(key, node.right.key) < 0)
node = rotateWithRightChild(node);
else
node = doubleRotateWithRight(node);
}
} else {
if(node.valuesList.size() > 1) {
node.valuesList.remove(value);
return node;
} else {
if(node.left == null && node.right == null)
return null;
if(node.left == null) return balance(node.right);
if(node.right == null) return balance(node.left);
Node smallestNode = smallestNode(node.right);
node = smallestNode;
node.right = remove(key, value, node.right);
return balance(node);
}
}
return balance(node);
}
private Node rotateWithLeftChild(Node node2) {
Node node1 = node2.left;
node2.left = node1.right;
node1.right = node2;
node2.height = Math.max(height(node2.left), height(node2.right)) + 1;
node1.height = Math.max(height(node1.left), node2.height) + 1;
return node1;
}
private Node rotateWithRightChild(Node node1) {
Node node2 = node1.right;
node1.right = node2.left;
node2.left = node1;
node1.height = Math.max(height(node1.left), height(node1.right)) + 1;
node2.height = Math.max(height(node2.left), node1.height) + 1;
return node2;
}
private Node doubleRotateWithLeft(Node node) {
node.left = rotateWithRightChild(node.left);
return rotateWithLeftChild(node);
}
private Node doubleRotateWithRight(Node node) {
node.right = rotateWithLeftChild(node.right);
return rotateWithRightChild(node);
}
private Node balance(Node node) {
node.height = Math.max(height(node.left), height(node.right)) + 1;
return node;
}
private Node smallestNode(Node node) {
if(node.left == null) return node;
else return smallestNode(node.left);
}
当我调试我的代码时,测试中的计数器最终只有一个,并且列表中还有一个项目。由于一些奇怪的原因,这是最后的第49本书,我不明白为什么:s
提前感谢您的帮助!
答案 0 :(得分:0)
因为我实例化 rootNode 在开始时 null ,所以当调用remove方法时我实际上并没有设置rootNode 。因此,它永远不会删除根。
因此,为了解决这个错误,我补充说:
rootNode = remove(key, value, rootNode);
第一次执行remove方法!
非常感谢您阅读:)