Question

我希望能够计算SQL Server 2008中某些事件之间的总时间。

我有一张表格如下：

UserId   Event      EventTimestamp
+-------+----------+---------------+
 1       CheckedIn  14-05-15 10:01
 2       CheckedIn  14-05-15 10:15
 3       CheckedIn  14-05-15 10:17
 1       CheckedOut 14-05-15 10:25
 1       Logout     14-05-15 10:26

如果您查看表格，用户可以办理登机手续，然后可以退房，然后离线。

我想计算一个人登记到他们结账的点之间的时间，每个星期的持续时间（登记入住和结账时间）小于10分钟。

到目前为止，我已成功按周分组，但我似乎无法计算这些事件之间的持续时间（将按此顺序发生）...

select      
   'Week ' + cast(datepart(wk, EventUpdateStamp) as varchar(2)) Week,     
    UserId,
    Event 
from MyTable 
group by datepart(wk, EventUpdateStamp), UserId, Event

我希望得到如下结果：

UserId   TotalSessionCheckInTimeMinutes  WeekNumber   
+-------+------------------------------+---------------+
 1       24                             43

以第一行为例：

1是用户ID
24是他之间的总持续时间（分钟）办理入住和退房手续
43是一年中的周数

我只想在办理登机手续时办理登机手续。不想在退房和退出之间进行衡量（换句话说，衡量他登记的时间）。

Answer 1

试试这个：

SELECT t1.UserId, 
    DATEDIFF(minute,
        t1.EventTimestamp,
        (SELECT MIN(t3.EventTimestamp)
        FROM MyTable t3
        WHERE t3.UserId = t1.UserId
        AND t3.EventTimestamp> t1.EventTimestamp)
    ), 
   CAST(DATEPART(wk, EventTimestamp) as varchar(2)) Week
FROM MyTable t1
WHERE EXISTS(
    SELECT 'NEXT'
    FROM MyTable t2
   WHERE t2.UserId = t1.UserId
   AND t2.EventTimestamp> t1.EventTimestamp
   AND t2.Event != 'Logout')

<强> SqlFiddle

转到here

Answer 2

你可以试试这个：

SELECT DISTINCT M.UserId, DATEPART(HOUR,A.TotalSessionCheckInTimeMinutes)*60 + DATEPART(MINUTE,A.TotalSessionCheckInTimeMinutes) AS TotalSessionCheckInTimeMinutes, DATEPART(WEEKDAY, M.EventTimestamp) FROM Mytable M
     CROSS APPLY (
        SELECT CAST((M1.EventTimestamp - M2.EventTimestamp) AS TIME) AS TotalSessionCheckInTimeMinutes
        FROM Mytable M1
          CROSS JOIN Mytable M2
            WHERE M1.Event = 'CheckOut' AND M2.Event = 'CheckIn' AND M1.UserId = M.UserId) AS A
UNION ALL
SELECT DISTINCT M.UserId, A.TotalSessionCheckInTimeMinutes, DATEPART(WEEKDAY, M.EventTimestamp) FROM Mytable M
     CROSS APPLY (
       SELECT CAST((M1.EventTimestamp - M2.EventTimestamp) AS TIME) AS TotalSessionCheckInTimeMinutes
       FROM Mytable M1
          CROSS JOIN Mytable M2
            WHERE M1.Event = 'LogOut' AND M2.Event = 'CheckIn' AND M1.UserId = M.UserId) AS A

SQL Server 2008查询以计算连续事件之间的总时间

2 个答案: