Question

我的查询有问题我不知道如何处理oracle但是当我尝试使用相同的SQL代码时它正在工作，但是它在编译时向我显示上述错误我认为问题出在查询中，请有人帮助，如果知道如何处理这个。谢谢

//头等舱

package com.caveofprogramming.spring.test;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.util.List;
import javax.sql.DataSource;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.RowMapper;
import org.springframework.jdbc.core.namedparam.BeanPropertySqlParameterSource;
import org.springframework.jdbc.core.namedparam.MapSqlParameterSource;
import org.springframework.stereotype.Component;

    @Component
    ("offersDao")
    public class OffersDAO {
        private JdbcTemplate jdbc;
        @Autowired`enter code here`
        public void setDataSource(DataSource jdbc) {
            this.jdbc = new JdbcTemplate(jdbc);
        }
    public boolean create(Offer offer) {
    BeanPropertySqlParameterSource params = new BeanPropertySqlParameterSource(offer);
    return jdbc.update("INSERT INTO offers " + " ( id, name, email, text) "
                    + " VALUES " + " ( :id, :name, :email, :text) ", params) == 1;
    }
    }

//第二课

package com.caveofprogramming.spring.test;

public class Offer {

    private int id;
    private String name;
    private String email;
    private String text;

    public Offer() {

    }

    public Offer(int id, String name, String email, String text) {

        this.id = id;
        this.name = name;
        this.email = email;
        this.text = text;
    }

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public String getText() {
        return text;
    }

    public void setText(String text) {
        this.text = text;
    }

    @Override
    public String toString() {
        return "Offer [id=" + id + ", name=" + name + ", email=" + email
                + ", text=" + text + "]";
    }

}

//第3主要课程

package com.caveofprogramming.spring.test;

import java.util.List;

import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import org.springframework.dao.DataAccessException;
import org.springframework.jdbc.CannotGetJdbcConnectionException;

public class App {

    public static void main(String[] args) {

        ApplicationContext context = new ClassPathXmlApplicationContext(
                "com/caveofprogramming/spring/test/beans/beans.xml");

        OffersDAO offersDao = (OffersDAO) context.getBean("offersDao");

        try {

            Offer offer1 = new Offer(10, "khan", "G@G.com", "GG");
            Offer offer2 = new Offer(11, "khan", "M@G.com", "GG");
            Offer offer3 = new Offer(12, "khan", "V@G.com", "GG");
            offersDao.create(offer1);
            offersDao.create(offer2);
            offersDao.create(offer3);

        } catch (CannotGetJdbcConnectionException ex) {
            System.out.println("Unable to connect to database");
        } catch (DataAccessException ex) {
            System.out.println(ex.getMessage());
            System.out.println(ex.getClass());
        }

        ((ClassPathXmlApplicationContext) context).close();
    }

}

Answer 1

  i tried 





       public boolean create (Offer offer){

        return jdbc.update("insert into offers (firstno,secondno,thirldno) values
     ( '" +offer.getFirstno() + "', '" +offer.getSecondno() +"' ,'"+offer.getThirldno()+"')")==1;

 }

而不是

  public boolean create(Offer offer) {
    BeanPropertySqlParameterSource params = new BeanPropertySqlParameterSource(offer);
    return jdbc.update("INSERT INTO offers " + " ( id, name, email, text) "
                    + " VALUES " + " ( :id, :name, :email, :text) ", params) == 1;
    }

现在它以这种方式工作。好吧，它没有回答我，但无论如何这是我发现以另一种方式处理上述错误，但我仍然没有找到上一个查询中可能出现的错误。感谢各位朋友:) Happy Coding

SQL状态[null];错误代码[17004];列类型无效;嵌套异常是java.sql.SQLException：列类型无效

1 个答案: