Question

我们使用自己的数据源，它建立在PoolDataSourceFactory

之上

<bean id="dataSource" class="oracle.ucp.jdbc.PoolDataSourceFactory"
      factory-method="getPoolDataSource" lazy-init="true" >
    <property name="connectionFactoryClassName" value="oracle.jdbc.pool.OracleDataSource"/>
    <property name="user" value="${jdbc.username}" />
    <property name="password" value="${jdbc.password}" />
    <property name="URL" value="${jdbc.url}" />
    <property name="connectionWaitTimeout" value="30" />
    <property name="minPoolSize" value="3"/>
    <property name="maxPoolSize" value="20"/>
    <property name="abandonedConnectionTimeout" value="300"/>
    <property name="inactiveConnectionTimeout" value="900"/>
    <property name="validateConnectionOnBorrow" value="true"/>
    <property name="exceptionManager" value="exceptionManager"/> 
</bean>

Tomcat服务器日志：

2017-10-17 20：33：25,913错误[http-nio-8101-exec-4] u： - JdbcStoredProcedureWrapper.selectUserDetails：无法执行存储过程：Exception [{}] org.springframework.jdbc.UncategorizedSQLException ：CallableStatementCallback;未分类SQL的SQLException [{？ =致电SP_NAME（？，？，？，）}]; SQL状态[null];错误代码[31];连接已关闭：连接已关闭;嵌套异常是java.sql.SQLException：连接已关闭：在org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate的org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate（AbstractFallbackSQLExceptionTranslator.java:84）处关闭连接。（AbstractFallbackSQLExceptionTranslator.java:81）org.springframework上的org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate（AbstractFallbackSQLExceptionTranslator.java:81）org.springframework.jdbc.core.JdbcTemplate.execute（JdbcTemplate.java:1137）。 jdbc.core.JdbcTemplate.call（JdbcTemplate.java:1173）atg.springframework.jdbc.object.StoredProcedure.execute（StoredProcedure.java:142）at com.vodafone.gdsp.provisioning.dataaccess.jdbc.JdbcStoredProcedureCaller.execute（ JdbcStoredProcedureCaller.java:561）at com.vodafone.gdsp.provisioning.dataaccess.jdbc.JdbcStore

如果有任何帮助，我会坚持这个问题

请帮我解决上述问题

Answer 1

经过一周的努力，我终于解决了问题：

解决方案：很可能是基于全局临时表（GTT）打开游标，该表是使用ON COMMIT DELETE ROWS选项创建的。并且ORA-08103：对象不再存在的原因错误是紧跟在delete语句之后的commit语句。 DBA团队不同意将GTT更改为提交保留行，所以最后我在Java服务层[实现Spring - 程序化事务]中添加了代码库但忘记添加transactionManager.rollback（status）int catch块这导致了连接关闭错误。

FiX：

package com.test;

import java.util.List;
import javax.sql.DataSource;

import org.springframework.dao.DataAccessException;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.transaction.PlatformTransactionManager;
import org.springframework.transaction.TransactionDefinition;
import org.springframework.transaction.TransactionStatus;
import org.springframework.transaction.support.DefaultTransactionDefinition;

public class StudentJDBCTemplate implements StudentDAO {
   private DataSource dataSource;
   private JdbcTemplate jdbcTemplateObject;
   private PlatformTransactionManager transactionManager;

   public void setDataSource(DataSource dataSource) {
      this.dataSource = dataSource;
      this.jdbcTemplateObject = new JdbcTemplate(dataSource);
   }
   public void setTransactionManager(PlatformTransactionManager transactionManager) {
      this.transactionManager = transactionManager;
   }
   public void create(String name, Integer age, Integer marks, Integer year){
      TransactionDefinition def = new DefaultTransactionDefinition();
      TransactionStatus status = transactionManager.getTransaction(def);

      try {
         String SQL1 = "insert into Student (name, age) values (?, ?)";
         jdbcTemplateObject.update( SQL1, name, age);

         // Get the latest student id to be used in Marks table
         String SQL2 = "select max(id) from Student";
         int sid = jdbcTemplateObject.queryForInt( SQL2 );

         String SQL3 = "insert into Marks(sid, marks, year) " + "values (?, ?, ?)";
         jdbcTemplateObject.update( SQL3, sid, marks, year);

         System.out.println("Created Name = " + name + ", Age = " + age);
         transactionManager.commit(status);
      } 
      catch (DataAccessException e) {
         System.out.println("Error in creating record, rolling back");
         **transactionManager.rollback(status);**
         throw e;
      }
      return;
   }
   public List<StudentMarks> listStudents() {
      String SQL = "select * from Student, Marks where Student.id=Marks.sid";
      List <StudentMarks> studentMarks = jdbcTemplateObject.query(SQL, 
         new StudentMarksMapper());

      return studentMarks;
   }
}

异常SQL状态[null];错误代码[31];连接已关闭：连接已关闭;嵌套异常是java.sql.SQLException

1 个答案: