Question

我有二维数组，如：

{2 , 6 , 46, 8 , 7 , 25, 64 , 9 , 10},
{6 , 10, 50, 12, 11, 29, 68 , 13, 14},
{46, 50, 90, 52, 51, 69, 108, 53, 54}

如何找到重复的元素，例如'6', '46' and '50'？

我的代码找到连续的重复项：

    for (int i = 0; i < a2.length; i++) {
        for (int j = 0; j < a2[i].length; j++) {
            cursor = a2[i][j];

            if(j + 1 < a2[i].length){
                if(cursor == a2[i][j + 1]){
                    System.out.println(cursor + "has duplicate in this array");
                }
            }
        }
    }

Answer 1

迭代所有元素并将其保存在临时集中当您遇到重复时，列表将包含它。

$Timeout=10000000;
$fileName = "0.iso";
$data = "C:\\$fileName";
$url = "http://nexus.lab.local:8081/nexus/content/sites/myproj/$fileName";
#$buffer = [System.IO.File]::Open("$data",[System.IO.Filemode]::Open, [System.IO.FileAccess]::Read) #Err Cannot convert argument "buffer", with value: "System.IO.FileStream", for "Write" to type "System.Byte[]": 
#$buffer = gc -en byte $data # too much space in memory 
$buffer = [System.IO.File]::ReadAllBytes($data) #Limit 2gb
[System.Net.HttpWebRequest] $webRequest = [System.Net.WebRequest]::Create($url)
$webRequest.Timeout = $timeout
$webRequest.Method = "POST"
$webRequest.ContentType = "application/data"
#$webRequest.ContentLength = $buffer.Length;
$webRequest.Credentials = New-Object System.Net.NetworkCredential("admin", "admin123");

$requestStream = $webRequest.GetRequestStream()
$requestStream.Write($buffer, 0, $buffer.Length)
$requestStream.Flush()
$requestStream.Close()

[System.Net.HttpWebResponse] $webResponse = $webRequest.GetResponse()
$streamReader = New-Object System.IO.StreamReader($webResponse.GetResponseStream())
$result = $streamReader.ReadToEnd()
return $result
$stream.Close()

输出：

[50,6,10,46]

Answer 2

试试这段代码： -

import java.util.Arrays;
import java.util.List;

public class ArrayTest {

    public static void main(String[] args) {

        Integer[][] myarray = new Integer[][]{
                  { 10, 20, 30, 40 },
                  { 50, 77, 60, 70 },
                  { 33, 22, 88, 99 },
                  { 21, 66, 65, 21 } 
                };
        int i,j;
        for(i=0;i<myarray.length;i++)
        {
            for(j=0;j<myarray.length;j++)
            {
                int temp= myarray[i][j];
                 myarray[i][j]=0;
                 List<Integer> rowvalues = Arrays.asList(Arrays.asList(myarray).get(i));
                 Boolean b=rowvalues.contains(temp) ;
                 if(b==true)
                 {
                     System.out.println("duplicate at ["+i+"]["+j+"] is: "+temp);
                 }
                 myarray[i][j]=temp;
            }
        }




    }

}

在二维数组中搜索重复项

2 个答案: