我想从异步任务返回字符串结果。
System.Threading.Tasks.Task.Run(async () => await audatex.UploadInvoice(assessment, fileName));
public async Task UploadInvoice(string assessment, string fileName)
{
//Do stuff
return string;
}
异步编程让我困惑,有人可以解释一下吗?
答案 0 :(得分:22)
异步编程可能需要一段时间才能解决问题,所以我会发布对我有用的内容,以防它帮助其他任何人。
如果要将业务逻辑与异步代码分开,可以使UploadInvoice方法保持无异步:
private string UploadInvoice(string assessment, string filename)
{
// Do stuff
Thread.Sleep(5000);
return "55";
}
然后你可以创建一个异步包装器:
private async Task<string> UploadInvoiceAsync(string assessment, string filename)
{
return await Task.Run(() => UploadInvoice(assessment, filename));
}
给你选择致电:
public async Task CallFromAsync()
{
string blockingInvoiceId = UploadInvoice("assessment1", "filename");
string asyncInvoiceId = await UploadInvoiceAsync("assessment1", "filename");
}
有时您可能需要从非异步方法调用异步方法。
// Call the async method from a non-async method
public void CallFromNonAsync()
{
string blockingInvoiceId = UploadInvoice("assessment1", "filename");
Task<string> task = Task.Run(async () => await UploadInvoiceAsync("assessment1", "filename"));
task.Wait();
string invoiceIdAsync = task.Result;
}
----编辑:添加更多示例,因为人们发现这很有用----
有时您希望等待任务,或者在完成时使用方法继续执行任务。这是一个可以在控制台应用程序中运行的工作示例。
class Program
{
static void Main(string[] args)
{
var program = new Program();
program.Run();
Console.ReadKey();
}
async void Run()
{
// Example 1
Console.WriteLine("#1: Upload invoice synchronously");
var receipt = UploadInvoice("1");
Console.WriteLine("Upload #1 Completed!");
Console.WriteLine();
// Example 2
Console.WriteLine("#2: Upload invoice asynchronously, do stuff while you wait");
var upload = UploadInvoiceAsync("2");
while (!upload.IsCompleted)
{
// Do stuff while you wait
Console.WriteLine("...waiting");
Thread.Sleep(900);
}
Console.WriteLine("Upload #2 Completed!");
Console.WriteLine();
// Example 3
Console.WriteLine("#3: Wait on async upload");
await UploadInvoiceAsync("3");
Console.WriteLine("Upload #3 Completed!");
Console.WriteLine();
// Example 4
var upload4 = UploadInvoiceAsync("4").ContinueWith<string>(AfterUploadInvoice);
}
string AfterUploadInvoice(Task<string> input)
{
Console.WriteLine(string.Format("Invoice receipt {0} handled.", input.Result));
return input.Result;
}
string UploadInvoice(string id)
{
Console.WriteLine(string.Format("Uploading invoice {0}...", id));
Thread.Sleep(2000);
Console.WriteLine(string.Format("Invoice {0} Uploaded!", id));
return string.Format("<{0}:RECEIPT>", id); ;
}
Task<string> UploadInvoiceAsync(string id)
{
return Task.Run(() => UploadInvoice(id));
}
}
答案 1 :(得分:18)
您的方法应该返回Task<string>
,而不是Task
:
public async Task<string> UploadInvoice(string assessment, string fileName)
{
//Do stuff
return string;
}
答案 2 :(得分:3)
这样做:
public async Task<string> UploadInvoice(string assessment, string fileName)
然后await
结果:
string result = await UploadInvoice("", "");
此处可以看到更多示例:
答案 3 :(得分:0)
public async Task<string> UploadInvoice(string assessment, string fileName)
{
string result = GetResultString();//Do stuff
return Task.FromResult(result);
}