Question

我正在尝试自动化Web应用程序。我应该点击一个链接，它会打开一个打印窗口。我无法在selenium自动化中实现这一点。所以我使用ctypes来做按键式按键，输入关键事件。下面是我为实现这一目标而开发的库。我通过调用相应的方法来完成事件。

import ctypes
import time

SendInput = ctypes.windll.user32.SendInput

# C struct redefinitions 
PUL = ctypes.POINTER(ctypes.c_ulong)
class KeyBdInput(ctypes.Structure):
    _fields_ = [("wVk", ctypes.c_ushort),
                ("wScan", ctypes.c_ushort),
                ("dwFlags", ctypes.c_ulong),
                ("time", ctypes.c_ulong),
                ("dwExtraInfo", PUL)]

class HardwareInput(ctypes.Structure):
    _fields_ = [("uMsg", ctypes.c_ulong),
                ("wParamL", ctypes.c_short),
                ("wParamH", ctypes.c_ushort)]

class MouseInput(ctypes.Structure):
    _fields_ = [("dx", ctypes.c_long),
                ("dy", ctypes.c_long),
                ("mouseData", ctypes.c_ulong),
                ("dwFlags", ctypes.c_ulong),
                ("time",ctypes.c_ulong),
                ("dwExtraInfo", PUL)]

class Input_I(ctypes.Union):
    _fields_ = [("ki", KeyBdInput),
                 ("mi", MouseInput),
                 ("hi", HardwareInput)]

class Input(ctypes.Structure):
    _fields_ = [("type", ctypes.c_ulong),
                ("ii", Input_I)]

# Actuals Functions
class KeyEvents :
    def PressKey(self,hexKeyCode):

        extra = ctypes.c_ulong(0)
        ii_ = Input_I()
        ii_.ki = KeyBdInput( hexKeyCode, 0x48, 0, 0, ctypes.pointer(extra) )
        x = Input( ctypes.c_ulong(1), ii_ )
        SendInput(1, ctypes.pointer(x), ctypes.sizeof(x))

    def ReleaseKey(self,hexKeyCode):

        extra = ctypes.c_ulong(0)
        ii_ = Input_I()
        ii_.ki = KeyBdInput( hexKeyCode, 0x48, 0x0002,0,ctypes.pointer(extra) )
        x = Input( ctypes.c_ulong(1), ii_ )
        SendInput(1, ctypes.pointer(x), ctypes.sizeof(x))


    def PressAltTab(self):
        '''
        Press Alt+Tab and hold Alt key for 2 seconds in order to see the     overlay
        '''

        self.PressKey(0x012) #Alt
        self.PressKey(0x09) #Tab
        self.ReleaseKey(0x09) #~Tab
        time.sleep(2)       
        self.ReleaseKey(0x012)

    def PressTab(self):
        '''
        Press Tab Key
        '''
        #self.AltTab()          
        self.PressKey(0x09) #Tab
        self.ReleaseKey(0x09)

def PressEnter(self):
    '''
    PressEnter
    '''
    #self.AltTab()
    self.PressKey(0x0D)#Enter Key
    self.ReleaseKey(0x0D)

但是现在当我在linux中使用代码时，我得到以下错误

File "KeyEvents.py", line 4, in <module>
SendInput = ctypes.windll.user32.SendInput
AttributeError: 'module' object has no attribute 'windll'

我不明白这里出了什么问题。我是python的新手。请在这里帮助我。我应该做些什么来实现linux中的按键事件？

Answer 1

我在Raspian Jessie（Raspberry Pi）上运行的代码也遇到了同样的问题。我认为这是因为windll.user32.SendInput仅适用于Windows。看起来它没有跨平台的灵活性..

如果您需要在Linux上执行Keypress事件，可以尝试使用xdotools。我认为这非常简单，应该可以满足您的所有需求。

要安装，只需执行

sudo apt-get install xdotool

和

xdotool键alt + Tab

对于alt + Tab键按下。

有关详细信息，请参阅 http://xmodulo.com/simulate-key-press-mouse-movement-linux.html

AttributeError：＆＃39;模块＆＃39;对象没有属性＆＃39; windll＆＃39;在python中

1 个答案: