Javascript - 计算围绕中心点的四个角的地理坐标点

Question

我有一个区域的中心点坐标（lng，lat）我想要计算围绕这个中心点的边界框中四个角的坐标（lng，lat）。从中心到每个角落的距离是10米。

插图：

如何在Javascript中执行此操作？

是否有一个图书馆可以存放这样的东西，还是我必须把那些多年无视Allard夫人三角学课的大脑弄脏？

Answer 1

基于Bruno Pinto给出的答案here 我最终创建并使用了它：

function getBoundingBox(pLatitude, pLongitude, pDistanceInMeters) {


            var latRadian = pLatitude.toRad();

            var degLatKm = 110.574235;
            var degLongKm = 110.572833 * Math.cos(latRadian);
            var deltaLat = pDistanceInMeters / 1000.0 / degLatKm;
            var deltaLong = pDistanceInMeters / 1000.0 / degLongKm;


            var topLat = pLatitude + deltaLat;
            var bottomLat = pLatitude - deltaLat;
            var leftLng = pLongitude - deltaLong;
            var rightLng = pLongitude + deltaLong;

            var northWestCoords = topLat + ',' + leftLng;
            var northEastCoords = topLat + ',' + rightLng;
            var southWestCoords = bottomLat + ',' + leftLng;
            var southEastCoords = bottomLat + ',' + rightLng;

            var boundingBox = [northWestCoords, northEastCoords, southWestCoords, southEastCoords];


            return boundingBox;
}

if (typeof(Number.prototype.toRad) === "undefined") {
  Number.prototype.toRad = function() {
  return this * Math.PI / 180;
 }
}

Answer 2

您可以查看以下功能： -

/*The getRectCoordinates takes the coordinates of the center point 
and the radial distance at which you want to find the coordinates*/
function getRectCoordinates (x,y,r) {
	//theta is the angle hard-coded to 45 degrees to think as the square 
	var theta = Math.PI/4,
	cos = Math.cos,
	sin = Math.sin;
	return {
		'topRight' : {
			'x' : x + r*cos(theta),
			'y' : y + r*sin(theta)
		},
		'bottomRight' : {
			'x' : x + r*cos(theta),
			'y' : y - r*sin(theta)
		},
		'topLeft' : {
			'x' : x - r*cos(theta),
			'y' : y + r*sin(theta)
		},
		'bottomLeft' : {
			'x' : x + r*cos(theta),
			'y' : y - r*sin(theta)
		}
	}
}

//An example for this (Check console for output): 
console.log(getRectCoordinates(2,3,10));

让我知道你的问题是否解决了兄弟。

Answer 3

让(x, y)成为中心的坐标，如下图所示：

然后您可以通过以下方式实际计算坐标：

/* Returns an array of arrays, each one corresponding to each point's
   coordinates (x, y) */
function getCoordinatesSquare (distance_to_center, x, y)
{
    var points = [];
    var dx = distance_to_center * Math.sin(Math.PI / 4);
    var dy = distance_to_center * Math.cos(Math.PI / 4);

    points[0] = [x - dx, y - dy]; // (x1, y1)
    points[1] = [x - dx, y + dy]; // (x2, y2)
    points[2] = [x + dx, y + dy]; // (x3, y3)
    points[3] = [x + dx, y - dy]; // (x4, y4)

    return points;
}

/* Set the initial conditions. */
var distance_to_center = 10;
var x = 4;
var y = 5;

/* Calculate. */
var coordinates = getCoordinatesSquare (distance_to_center, x, y);

/* Test the results. */
for (var i = 0; i < coordinates.length; i++){
    console.log ("(" + coordinates[i][0] + ", " + coordinates[i][1] + ") \n");
}

在这种情况下，输出将是：

(-3.0710678118654746, -2.0710678118654755)
(-3.0710678118654746, 12.071067811865476) 
(11.071067811865476, 12.071067811865476) 
(11.071067811865476, -2.0710678118654755) 

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