Question

import random

randomOne = random.randint(1,10)
    print(randomOne)
randomTwo = random.randint(1,10)
    print(randomTwo)

b = randomTwo * 2
while b != randomOne:
    print("Your first number is not a multiple of the second number!")
x = input('Press Enter to try again.')


randomOne = random.randint(1,10)
print(randomOne)
randomTwo = random.randint(1,10)
print(randomTwo)

if randomTwo * 2 == randomOne:
    print("Your first number is a multiple of the second number!")

当第二个数字不是第一个数字的倍数时，我无法循环此代码。而且，如何在条件为真时完成程序，即第二个数字是第一个数字的倍数。

Answer 1

在Python中，与大多数其他编程语言不同，代码缩进很重要。由于缩进已得到修复，因此以下内容应该有效。此外，您需要在while循环中重新计算b的值，这样循环最终会失败。

import random

randomOne = random.randint(1,10)
print(randomOne)
randomTwo = random.randint(1,10)
print(randomTwo)

b = randomTwo * 2
while b != randomOne:
    print("Your first number is not a multiple of the second number!")
    x = input('Press Enter to try again.')

    randomOne = random.randint(1,10)
    print(randomOne)
    randomTwo = random.randint(1,10)
    print(randomTwo)
    b = randomTwo * 2

# No need to check if it is a multiple since it must be to break the loop
print("Your first number is a multiple of the second number!")

如果您的目标是找到两个数字的组合，其中第一个真正是第二个数字的倍数，您可以尝试这样的事情：

import random

randomOne = random.randint(1,10)
print(randomOne)
randomTwo = random.randint(1,10)
print(randomTwo)

b = randomOne / randomTwo
# If b is an integer, then it divided evenly
while b != int(b):
    print("Your first number is not a multiple of the second number!")
    x = input('Press Enter to try again.')

    randomOne = random.randint(1,10)
    print(randomOne)
    randomTwo = random.randint(1,10)
    print(randomTwo)
    b = randomOne / randomTwo

if randomTwo * 2 == randomOne:
    print("Your first number is a multiple of the second number!")

如何正确循环此代码？我无法让它发挥作用。编码仍然很新

1 个答案: