Question

苦苦挣扎，似乎无法让它发挥作用。这是我需要做的：

1.询问用户今年的美化季节是多少个星期。

2.动态创建一个双浮点数据数组，可用于存储本赛季每周的销售额。

3.使用for循环，让用户输入本赛季的销售数据。

4.将数组（及其大小）传递给一个函数，该函数将在一个漂亮的表中显示周内的所有销售。

5.拨打另一个函数，将数组作为参数，并将总计季节的销售额（将总数返回到主函数）。

6.该程序告诉用户本赛季的总销售额和每周的平均销售额。

7.删除分配的内存后，将指针设置为0。

任何帮助总是让我不太了解函数或指针。而且我已经读了很多!!

#include <iostream>
#include <iomanip>
using namespace std;


int Weeks = 0;
double total;
double sales;
void SalesTable(int);
double Total (int, double[]);
double average;

int main()
{ 

   double Season[Weeks];

   cout << "How many weeks were in the landscaping season this year: ";
   cin >> Weeks;

   for (int i = 1; i<Weeks+1; i++)
   {
      cout << "Enter sales data for week " << i <<": ";
      cin >> sales;
   }

Season[Weeks]=sales;

SalesTable(Weeks);
Total(Weeks, Season);

average = total/Weeks;

cout << "The total sales for the season are: "<<setprecision(2)<<showpoint<<fixed<<total<<        endl;
cout << "The average weekly sales were: "<<setprecision(2)<<showpoint<<fixed<<average;
return 0;
}
void SalesTable(int Weeks)
{
for(int i = 1; i<Weeks+1; i++)
{
    cout << "Sales for week "<< i <<":" << sales <<endl;
}
}
double Total(int Weeks, double Season[])
{
for(int i = 1; i<Weeks+1; i++)
{
    total += Season[Weeks];
}
return total;
}

Answer 1

好的，使用指针加倍它会做你需要的：

int Weeks = 0;
double total;
double sales;
void SalesTable(int, double*);
double Total (int, double*);
double average;
int main ()
{
    double *Season;
    cout << "How many weeks were in the landscaping season this year: ";
    cin >> Weeks;

            Season = new double [ Weeks ];

    for (int i = 1; i<Weeks+1; i++)
    {
       cout << "Enter sales data for week " << i <<": ";
       cin >> sales;
       Season[i-1]=sales;
    }



    SalesTable(Weeks, Season);
    Total(Weeks, Season);

    average = total/(double)Weeks;

    cout << "The total sales for the season are: "<<showpoint<<fixed<<total<<endl;
    cout << "The average weekly sales were: "<<showpoint<<fixed<<average;
    delete[] Season;
    return 0;
}

    void SalesTable(int Weeks,double *Season)
    {
        for(int i = 1; i<Weeks+1; i++)
        {
            cout << "Sales for week "<< i <<":" << Season[i-1]<<endl;
        }
    }

    double Total(int Weeks, double *Season)
    {
        for(int i = 1; i<Weeks+1; i++)
        {
            total += Season[i-1];
        }
        return total;
    }

Answer 2

由于我无法发表评论，我将发布一个新答案：

T-D提供的代码仍然无法正常工作：每个销售周的打印输出总是相同的，因为它不能访问Seasons数组内的元素。

void SalesTable(int Weeks)
{
    for(int i = 1; i<Weeks+1; i++)
    {
        cout << "Sales for week "<< i <<":" << Season[i - 1] << endl;
    }
}

另外，要动态创建一个允许用户在运行时控制数组大小的数组，请使用以下代码：

double *season = new double[Weeks];

由于您动态创建了数组，因此必须手动释放其资源：

delete[] season;

如何使此代码生效？

2 个答案: