我的情况是我正在尝试找一个随机数模式生成器代码,但我似乎无法找到它。我需要使用“1”,“2”,“3”,“4”,“5”和“6”来创建一个随机模式,有4个数字,如1111,1264,2564等。我试过这个,但它不是工作
public static void computer() {
List<Integer> template = Arrays.asList(1, 2, 3, 4, 5, 6);
for (int i = 0; i < 10; ++i) {
List<Integer> items = new ArrayList<Integer>(template);
Collections.shuffle(items);
System.out.println(items);
}
}
答案 0 :(得分:1)
试试这个:
Random r = new Random();
int number = 0;
int d = 1;
while (number < 1000) {
// generate number between 1-6
int num = r.nextInt(6) + 1;
number += num * d;
// increase the digit (units, tens, hundreds, thousands)
d *= 10;
}
System.out.println(number);
答案 1 :(得分:0)
public static void computer() {
List<Integer> template = Arrays.asList(1, 2, 3, 4, 5, 6);
Random r = new Random();
StringBuilder random = new StringBuilder();
for (int i = 0; i < 4; ++i) {
int create = r.nextInt(6);
// find in array between 1-6 index
int find = template.get(create);
random.append(String.valueOf(find));
}
System.out.println(random);
}
答案 2 :(得分:0)
Random r = new Random();
String s = "";
while(s.length() < 4)
{
int numpick = r.nextInt() % 6;
if(numpick > 0)
s += numpick;
}
return Integer.parseInt(s);
显然可以稍微刷一下,但我认为这是制定数字的最佳策略。