Question

我尝试在成功验证表单后发出ajax请求。如果我在,之后删除了url: 'loginprivate.php' php代码，但验证不行。如果我添加,验证工作，但不是PHP代码。成功的ajax请求后的重定向无论如何都不起作用。我怎样才能使其正常工作，可能在$(form).ajaxSubmit();时，我应该在哪里添加此行？

 $(document).ready(function () {
        $('#myform').validate({ // initialize the plugin
            rules: {
                username: {
                    required: true,
                    minlength: 2,
                    maxlength: 30
                },
                password: {
                    required: true,
                    minlength: 3,
                    maxlength: 30
                }
            },
            submitHandler: function (form) { // for demo
                $.ajax({
    type: 'post',
    url: 'loginprivate.php',   //url where you want to post the stuff.
    data:{
        username: 'root',
        password: ''
    },
    success: function(res){
        //here you will get res as response from php page, either logged in or some error.
         window.location.href = "http://localhost/localcorps/main.php";
    }
});
                return false; // for demo
            }
        });
    });

我的PHP代码：

    if(isset($_POST["submit"]))
    {
            $hostname='localhost';
            $username='root';
            $password='';

            unset($_POST['password']);
            $salt = ''; 
            for ($i = 0; $i < 22; $i++) { 
                    $salt .= substr('./ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789', mt_rand(0, 63), 1); 
            }
            $_POST['password'] = crypt($_POST['password'],'$2a$10$'.$salt);
            $new = 0;
            try {
                    $dbh = new PDO("mysql:host=$hostname;dbname=search",$username,$password);
                    $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); // <== add this line
                    $sql = "INSERT INTO users (username, password)
                    VALUES ('".$_POST["username"]."','".$_POST["password"]."')";
                    if ($dbh->query($sql)) {
                            echo "New Record Inserted Successfully";
                    }
                    else{
                            echo "Data not successfully Inserted.";
                    }
                    $new = $dbh->lastInsertId();
                    $dbh = null;
            }
            catch(PDOException $e)
            {
                    echo $e->getMessage();
            }
            if ($new > 0) 
            {

                $t = time() + 60 * 60 * 24 * 1000;
                setcookie("username", $_POST['username'], $t);
                setcookie("userid", $new , $t);
            } 
        else
            {

            }
    }

Answer 1

我的ajax添加此

data:{
    username: 'root',
    password: '',
    submit: true,// add this line as you are checking in php file.
},

jquery验证后的ajax请求

1 个答案: