Jquery的:
$(".sortimente").click(function(){
var sort = $(this).attr('value');
var dataId = "st="+ sort;
$.ajax ({
type: "POST",
url: "functii.php",
data: dataId,
cache: false,
success: function(html)
{ $("#text").html(html); }
});
});
$(".but-comanda").click(function(e){
e.preventDefault();
var produs = $(this).attr('value');
dataId = 'produs='+ produs;
$.ajax ({
type: "POST",
url: "cos.php",
data: dataId,
cache: false,
success: function(html)
{ $("#cos").html(html);}
});
});
.but_comanda
正在开始工作,但是,如果我按下.sortimente
,他就会停止工作,并且在cos.php
数组中保存收到的数据时不会添加任何内容。
cos.php
session_start();
if(!isset($_SESSION['cos']))
$_SESSION['cos'] = array();
if(!in_array($_POST['produs'],$_SESSION['cos']))
array_push($_SESSION['cos'], $_POST['produs']);
foreach($_SESSION['cos'] as $key)
echo $key."<br />";
如果我在php文件中有类.but-comanda
并且此文件是带有ajax的请求,则可能有问题?
<?php
function AfisareProduse($c = NULL, $p = NULL, $o = NULL, $d = NULL) {
include('configurare.php');
$pret = explode('-', $p);
if( $c != '')
$interogare = "SELECT * FROM `produse` WHERE `categorie` = '". $c ."' AND (`pret` BETWEEN " . $pret[0] . " AND " . $pret[1] . ") ORDER BY ". $d . " " . $o ;
else
$interogare = "SELECT * FROM `produse` WHERE `pret` BETWEEN " . $pret[0] . " AND " . $pret[1] . " ORDER BY ". $d . " " . $o ;
echo $interogare . "<br />";
$rezultat = $conexiune->query($interogare);
if($rezultat->num_rows > 0)
while($rand = $rezultat->fetch_array())
{
$id = $rand['id'];
$nume = $rand['nume'];
$categorie = $rand['categorie'];
$pret = $rand['pret'];
$imag = $rand['imag'];
echo "<div id='produs'> <div id='img-produs'><img src='Poze/".$categorie."/".$imag."'/></div>" .
" <div id='det-produs'> Produs: <span id='nume-produs'>" . $nume . "</span>".
" <br />Pret: " . $pret . "lei/Kg".
" <br />Categorie: " . $categorie .
" <p class='but-comanda' value='".$nume."' ><a href='##'>Comanda!</a></p></div></div>";
}
}
?>
请问,好吗?
答案 0 :(得分:0)
In&#34; .but-comanda&#34;点击您正在定义的事件&#34; dataId&#34;作为全球变量。那背后有什么特别的原因吗?
您可以尝试使用var?
作为前缀$(".but-comanda").click(function(e){
e.preventDefault();
var produs = $(this).attr('value');
var dataId = 'produs='+ produs;
$.ajax ({
type: "POST",
url: "cos.php",
data: dataId,
cache: false,
success: function(html)
{ $("#cos").html(html);}
});
});