Question

我正在尝试从字典中提取某些值并以特定方式显示它。我将在下面向您展示我的代码示例：

dict = [{'Titel': 'Rush', 'Name': 'Floris', 'Starttime': '20:30', 'Email': 'Floris@email.com', 'Supplier': 'RTL8', 'Surname': 'Cake', 'Code': 'ABC123'},
 {'Titel': 'Rush', 'Voornaam': 'Jaron', 'Starttime': '20:30', 'Email': 'JaronPie@email.com', 'Supplier': 'RTL8', 'Surname': 'Pie', 'Code': 'XYZ123'},
 {'Titel': 'Underneath', 'Name': 'Klaas', 'Starttime': '04:00', 'Email': 'Klassieboy@gmail.com', 'Supplier': 'RTL8', 'Surname': 'Klassie', 'Code': 'fbhwuq8674'}]

那是我的字典。我想要的输出是：

Titel, Starttime,
Surname, Name, Email

所以它看起来像这样：

Rush, 20:30, 
Cake, Floris, Floris@email.com
Pie, Jaron, JaronPie@email.com

Underneath, 04:00,
Klassie, Klaas, Klassieboy@gmail.com

Answer 1

我使用VKS的代码来构建它，感谢VKS：P

使用groupy，list comprehension和sting formatting

<强>代码：

from itertools import groupby
k = [{'Titel': 'Rush', 'Name': 'Floris', 'Starttime': '20:30', 'Email':      'Floris@email.com', 'Supplier': 'RTL8', 'Surname': 'Cake', 'Code': 'ABC123'},
{'Titel': 'Rush', 'Voornaam': 'Jaron', 'Starttime': '20:30', 'Email': 'JaronPie@email.com', 'Supplier': 'RTL8', 'Surname': 'Pie', 'Code': 'XYZ123'},
{'Titel': 'Underneath', 'Name': 'Klaas', 'Starttime': '04:00', 'Email': 'Klassieboy@gmail.com', 'Supplier': 'RTL8', 'Surname': 'Klassie', 'Code': 'fbhwuq8674'}]

lst=[(i["Titel"],i["Starttime"],i["Surname"],i.get("Name","None"), i["Email"]) for i in k]
lst.sort(key=lambda x:(x[0],x[1]))
for key,groups in groupby(lst,key=lambda x:(x[0],x[1])):
    print "{}\t{}".format(key[0],key[1])
    for value in groups:
        print "{}\t{}\t{}".format(value[2],value[3],value[4])
    print ""

<强>输出：

Rush    20:30
Cake    Floris  Floris@email.com
Pie     None    JaronPie@email.com

Underneath      04:00
Klassie Klaas   Klassieboy@gmail.com

Answer 2

k = [{'Titel': 'Rush', 'Name': 'Floris', 'Starttime': '20:30', 'Email':      'Floris@email.com', 'Supplier': 'RTL8', 'Surname': 'Cake', 'Code': 'ABC123'},
 {'Titel': 'Rush', 'Voornaam': 'Jaron', 'Starttime': '20:30', 'Email': 'JaronPie@email.com', 'Supplier': 'RTL8', 'Surname': 'Pie', 'Code': 'XYZ123'},
 {'Titel': 'Underneath', 'Name': 'Klaas', 'Starttime': '04:00', 'Email': 'Klassieboy@gmail.com', 'Supplier': 'RTL8', 'Surname': 'Klassie', 'Code': 'fbhwuq8674'}]

print [(i["Titel"],i["Starttime"],i["Surname"], i["Email"]) for i in k]

您可以使用此功能，您将获得所需信息的tuple。

Answer 3

def print_my_d(d):

     print(d[0]['Titel'], d[0]['Starttime'])
     for l in d[:2]:
         print(l['Surname'], l['Name'], l['Email'])
     print()
     print(d[2]['Titel'],d[2]['Starttime'])
     print("{}, {}, {}".format(d[2]['Surname'],d[2]['Name'], d[2]['Email']))


print_my_d(d)

Rush 20:30
Cake Floris Floris@email.com
Pie Jaron JaronPie@email.com

Underneath 04:00
Klassie, Klaas, Klassieboy@gmail.com

Python - 以特定方式从字典中提取信息

3 个答案: