我有一些带状态的顶级组件(RegisrationPage
),它将state / props传递给转储底层组件(InputField
,Dropdown
,Datepicker
)。
底层组件在回调的帮助下改变RegistrationPage
的状态。
问题: PureRenderMixin不起作用,因为我必须绑定传递给底层组件的状态更改回调。
问题: 如何让PureRenderMixin
以最优雅的方式运作?
让我们用代码解释它:
InputBlock:
const React = require('react'),
PureRenderMixin = require('react-addons-pure-render-mixin');
module.exports = React.createClass({
mixins: [PureRenderMixin],
propTypes: {
input: React.PropTypes.string,
onChange: React.PropTypes.func
},
render() {
//PROBLEM - is re-rendered each time , since onChange callback each time is an different object due bind method call
}
});
RegistrationPage:
RegistrationPage = React.createClass({
/**
* Since all state is held by `RegistrationPage` and bottom-level components are dump,
* I do _onFieldChange.bind - _onFieldChange should know which field should be changed
*/
render() {
return CreateFragment({
email: <InputBlock
input={this.state.email}
onChange={this._onFieldChange.bind(self, 'email')}/>,
firstName: <InputBlock
input={this.state.firstName}
onChange={this._onFieldChange.bind(self, 'firstName')}/>,
.........
});
},
_onFieldChange(key, event) {
//Save registered progress to store and re-render the component
AppActionCreators.saveRegisterProgress(this.state);
}
})
我的解决方法:只需将inputFieldName
作为额外属性传递,并在底层组件中进行绑定。
答案 0 :(得分:1)
问题是.bind()
每次调用它时都会返回一个新函数。要避免它,您应该在渲染之外创建函数。例如:
RegistrationPage = React.createClass({
render() {
return CreateFragment({
email: <InputBlock
input={this.state.email}
onChange={this._onEmailChange}/>,
firstName: <InputBlock
input={this.state.firstName}
onChange={this._onFirstNameChange}/>,
.........
});
},
_onFieldChange(key, event) {
//Save registered progress to store and re-render the component
AppActionCreators.saveRegisterProgress(this.state);
}
_onEmailChange() {
this._onFieldChange('email')
}
_onFirstNameChange() {
this._onFieldChange('firstName')
}
})