我需要找到2-D List的总和,但我只能找到第一个列表的总和。有人可以指点我或指导我,我也看到人们使用柜台。我们不允许使用柜台。
firstBorder.hidden = true
我将此作为列表值
def avg(lst):
i = 0
A = 0
for item in lst :
B = lst[i][A]+lst[i][A+1]+lst[i][A+2]
i = i +1
return B
当我执行时我只得到第一个列表的总和,但我需要得到整个列表的总和。
lsit = [[95, 92, 86], [66, 75, 54], [89, 72, 100], [34, 0, 0]]
答案 0 :(得分:1)
我对您的代码进行了一些最小的更改。按照评论
var newState = state.updateIn(['widgets'], function (list) {
return list.push(Immutable.fromJS({
name: 'Some widget2',
type: 'List',
defaultDataSource: 'daily',
dataSources: {}
}));
});
var newState1 = state.updateIn(['widgets'], function (list) {
return list.push(Immutable.fromJS({
name: 'Some widget2',
type: 'List',
defaultDataSource: 'daily',
dataSources: {}
}));
});
使用内置def avg(lst):
i = 0
A = 0
B = 0 # initialize
for item in lst :
B += lst[i][A]+lst[i][A+1]+lst[i][A+2] # Use +=
i = i +1 # Inside loop
return B
和gen-exp的替代方案是
sum
请注意您使用>>> lsit = [[95, 92, 86], [66, 75, 54], [89, 72, 100], [34, 0, 0]]
>>> sum(sum(i) for i in lsit)
763
查找总和
答案 1 :(得分:0)
展平列表并使用总和
pom.xml
输出
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.my</groupId>
<artifactId>automation</artifactId>
<version>1.0-SNAPSHOT</version>
<build>
<testSourceDirectory>src/test/java/com/my/tests</testSourceDirectory>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-source-plugin</artifactId>
<executions>
<execution>
<id>attach-sources</id>
<goals>
<goal>jar</goal>
</goals>
</execution>
</executions>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<version>3.3</version>
<configuration>
<source>1.7</source>
<target>1.7</target>
</configuration>
</plugin>
<plugin>
<inherited>true</inherited>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-deploy-plugin</artifactId>
<configuration>
<updateReleaseInfo>true</updateReleaseInfo>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-surefire-plugin</artifactId>
<version>2.18.1</version>
<configuration>
<parallel>methods</parallel>
<threadCount>10</threadCount>
<groups>com.my.testgroups.AutoTestsGroup</groups>
</configuration>
</plugin>
</plugins>
</build>
<profiles>
<profile>
<id>release-profile</id>
<activation>
<property>
<name>performRelease</name>
</property>
</activation>
</profile>
</profiles>
<dependencies>
<dependency>
<groupId>javax.xml.ws</groupId>
<artifactId>jaxws-api</artifactId>
<version>2.2.11</version>
</dependency>
<dependency>
<groupId>commons-io</groupId>
<artifactId>commons-io</artifactId>
<version>2.4</version>
</dependency>
<dependency>
<groupId>commons-lang</groupId>
<artifactId>commons-lang</artifactId>
<version>2.6</version>
</dependency>
<dependency>
<groupId>log4j</groupId>
<artifactId>log4j</artifactId>
<version>1.2.17</version>
</dependency>
<dependency>
<groupId>com.sun.xml.bind</groupId>
<artifactId>jaxb-impl</artifactId>
<version>2.2.11</version>
</dependency>
<dependency>
<groupId>org.glassfish.jaxb</groupId>
<artifactId>jaxb-runtime</artifactId>
<version>2.2.11</version>
</dependency>
<dependency>
<groupId>javax.xml.bind</groupId>
<artifactId>jaxb-api</artifactId>
<version>2.2.12</version>
</dependency>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>4.12</version>
</dependency>
</dependencies>
</project>
答案 2 :(得分:0)
您是否只是想在lsit中获取每个元素的总和?这样做......
import numpy as np
lsit = [[95, 92, 86], [66, 75, 54], [89, 72, 100], [34, 0, 0]]
np.sum(lsit)