如何使用Laravel 5.1执行原始查询?

时间:2015-10-10 02:07:47

标签: php mysql sql database laravel-5.1

所以我在我的数据库上运行这个小查询,它在MySQL Workbench中工作正常。 基本上,SELECT LEFT JOIN和UNION再次LEFT JOIN。

SELECT
    cards.id_card,
    cards.hash_card,
    cards.`table`,
    users.name,
    0 as total,
    cards.card_status,
    cards.created_at
FROM cards
LEFT JOIN users
ON users.id_user = cards.id_user
WHERE hash_card NOT IN ( SELECT orders.hash_card FROM orders )
UNION
SELECT
    cards.id_card,
    orders.hash_card,
    cards.`table`,
    users.name,
    sum(orders.quantity*orders.product_price) as total, 
    cards.card_status, 
    max(orders.created_at) 
FROM menu.orders
LEFT JOIN cards
ON cards.hash_card = orders.hash_card
LEFT JOIN users
ON users.id_user = cards.id_user
GROUP BY hash_card
ORDER BY id_card ASC

试图将其翻译成Laravel,但没有成功。

$cards = Card::selectRaw('cards.id_card, cards.hash_card ,cards.table, users.name, 0 as total, cards.card_status, cards.created_at as last_update')
                ->leftJoin('users','users.id_user','=','cards.id_user')
                ->whereNotIn( 'hash_card', Order::select('orders.hash_card')->get() )
                ->union(
                        Order::selectRaw('cards.id_card, orders.hash_card, cards.table, users.name, sum(orders.quantity*orders.product_price) as total, cards.card_status, max(orders.created_at) as last_update')
                        ->leftJoin('cards','cards.hash_card','=','orders.hash_card')
                        ->leftJoin('users','users.id_user','=','cards.id_user')
                )
                ->groupBy('hash_card')
                ->orderBy('cards.id_card','asc')
                ->get();

我收到了错误

  

Builder.php第1249行中的ErrorException:未定义属性:   照亮\数据库\雄辩\生成器:: $绑定

如何在Laravel中执行完全原始查询或在Laravel中以正确的方式编写查询?

3 个答案:

答案 0 :(得分:104)

我在this topic找到了解决方案,我对此进行了编码:

$cards = DB::select("SELECT
        cards.id_card,
        cards.hash_card,
        cards.`table`,
        users.name,
        0 as total,
        cards.card_status,
        cards.created_at as last_update
    FROM cards
    LEFT JOIN users
    ON users.id_user = cards.id_user
    WHERE hash_card NOT IN ( SELECT orders.hash_card FROM orders )
    UNION
    SELECT
        cards.id_card,
        orders.hash_card,
        cards.`table`,
        users.name,
        sum(orders.quantity*orders.product_price) as total, 
        cards.card_status, 
        max(orders.created_at) last_update 
    FROM menu.orders
    LEFT JOIN cards
    ON cards.hash_card = orders.hash_card
    LEFT JOIN users
    ON users.id_user = cards.id_user
    GROUP BY hash_card
    ORDER BY id_card ASC");

答案 1 :(得分:1)

    DB::statement("your query")

我用它为迁移中的列添加索引

答案 2 :(得分:-3)

您也可以以这种方式运行原始查询。

DB::table('setting_colleges')->first();