Question

我正在制作适用于Android的应用程序，并且在它的核心中它有一个节拍器。我需要在节拍中精确地发出声音。并且每第2个声音都被延迟了＃34; swing＆＃34;间隔百分比。我目前的代码如下：

public void play() {
    mainCountHandler.postDelayed(mainClick, 0);
    subCountHandler.postDelayed(subClick, (MILLIS_IN_MINUTE/ (2 * bpm)) * (100 + swing));
}

private Runnable mainClick = new Runnable()
{
    public void run()
    {
        playSound();
        mainCountHandler.postDelayed(this, MILLIS_IN_MINUTE / bpm);
    }
};

private Runnable subClick = new Runnable()
{
    public void run()
    {
        playSound();
        subCountHandler.postDelayed(this, MILLIS_IN_MINUTE / bpm);
    }
};

private void  playSound() {
    final MediaPlayer mp = MediaPlayer.create(context, SOUND);
    mp.start();
    mp.setOnCompletionListener(new MediaPlayer.OnCompletionListener() {
        public void onCompletion(MediaPlayer mp) {
            mp.release();
        };
    });

    ++currentBeat;
    if (currentBeat >= beatsCount) {
        if (loop) {
            currentBeat = 0;
        } else {
            stop();
        }
    }
}

这非常不准确。我尝试了 SoundPool ，并在 playSound 之外创建了 MediaPlayer ，并且没有任何重大变化。那么有任何修改或者可能有其他可以帮助我的Android类吗？

Answer 1

所以我能达到的最精确的节拍器看起来像这样：

public void play() {
    mainTimer = new Timer();
    subTimer = new Timer();
    mainTimerTask = new MyTimerTask();
    subTimerTask = new MyTimerTask();

    mainTimer.schedule(mainTimerTask, 0, MILLIS_IN_MINUTE / bpm);
    subTimer.schedule(subTimerTask, (300 * (100+swing)) / bpm, MILLIS_IN_MINUTE / bpm);

}

private void  playSound() {
    final MediaPlayer mp = MediaPlayer.create(context, SOUND);
    mp.start();
    mp.setOnCompletionListener(new MediaPlayer.OnCompletionListener() {
        public void onCompletion(MediaPlayer mp) {
            mp.release();
        };
    });
}

class MyTimerTask extends TimerTask {

    @Override
    public void run() {
        playSound();
    }
}

制作精确的机器人节拍器

1 个答案: