Question

以下查询根据用户投票的次数对投票进行排序...我想知道特定用户队列中的＃。

SELECT @s:=@s+1 serial_number, user_id, COUNT(slug_owner) as cnt 
FROM `votes_queue`,(SELECT @s:= 0) AS s 
GROUP BY slug_owner
ORDER BY cnt DESC 

serial_number | user_id | cnt 
3 | 19 | 8
2 | 14 | 4
1 | 13 | 2

基本上我需要反转serial_number列中的数字，这样我就可以根据投票判断用户13是＃3了。

Answer 1

在生成有序计数后分配序列号：

SELECT @s:=@s+1 serial_number, temp.*
FROM (
    SELECT user_id, COUNT(slug_owner) as cnt 
    FROM `votes_queue`,
    GROUP BY slug_owner
    ORDER BY cnt DESC
) temp, (SELECT @s:= 0) AS s

Answer 2

序列号不会反转，因为GROUP BY和变量不会混合。 ORDER BY很好。您可以使用@ hjpotter92的解决方案，但以下内容也解决了问题：

SELECT (@rn := @rn + 1) as serial_number, t.*
FROM (SELECT serial_number, user_id, COUNT(slug_owner) as cnt 
      FROM `votes_queue`
      GROUP BY slug_owner
     ) t CROSS JOIN
     (SELECT @rn := 0) params
ORDER BY cnt DESC;

我认为表现是一样的。我提供这个答案只是为了澄清实际问题是什么。

反转分组查询的序列号

2 个答案: