Question

所以，我试图计算MySQL查询中的平均值有点困难。我要做的是从两个表中读取数据，其中一个表很小，并且有条目描述房间，序列号，高程和有关传感器的其他数据。另一个表包含每个序列号的温度输出记录。这是每个表的一些示例数据。

+------------------+-------+------+-----------+---------+--------+-----------+
| serial           | room  | rack | elevation | type    | system | threshold |
+------------------+-------+------+-----------+---------+--------+-----------+
| 2D0008017075F210 | 2B211 | 5    |         5 | DS18S20 | test   |        68 |
| 1D00080170496D10 | 2B211 | 5    |         5 | DS18S20 | test   |        68 |
| 380008017037ED10 | 2B211 | 5    |         5 | DS18S20 | test   |        68 |
+------------------+-------+------+-----------+---------+--------+-----------+


+------------------+---------------------+---------+
| serial           | dtg                 | reading |
+------------------+---------------------+---------+
| 2D0008017075F210 | 2013-08-02 12:30:28 |    98.6 |
| 1D00080170496D10 | 2013-08-02 12:30:28 |    73.4 |
| 380008017037ED10 | 2013-08-02 12:30:28 |    79.7 |
| 2D0008017075F210 | 2013-08-02 12:30:38 |    98.6 |
| 1D00080170496D10 | 2013-08-02 12:30:38 |    73.4 |
| 380008017037ED10 | 2013-08-02 12:30:38 |    79.7 |
| 2D0008017075F210 | 2013-08-02 12:30:48 |    98.6 |
| 1D00080170496D10 | 2013-08-02 12:30:48 |    73.4 |
| 380008017037ED10 | 2013-08-02 12:30:48 |    79.7 |
| 2D0008017075F210 | 2013-08-02 12:30:58 |    98.6 |
| 1D00080170496D10 | 2013-08-02 12:30:58 |    73.4 |
| 380008017037ED10 | 2013-08-02 12:30:58 |    79.7 |
| 2D0008017075F210 | 2013-08-02 12:31:08 |    98.6 |
| 1D00080170496D10 | 2013-08-02 12:31:08 |    73.4 |
| 380008017037ED10 | 2013-08-02 12:31:08 |    79.7 |
| 2D0008017075F210 | 2013-08-02 12:31:18 |    98.6 |
| 1D00080170496D10 | 2013-08-02 12:31:18 |    73.4 |
| 380008017037ED10 | 2013-08-02 12:31:18 |    79.7 |
+------------------+---------------------+---------+

我有一个SQL查询，可以将数据格式化为一个表格，然后我将其转换为JSON并传递给Web浏览器进行可视化。它看起来与此类似，虽然有点不同，因为我正在使用存储过程来修改时间间隔。

SELECT sensor_data.serial, sensor_data.dtg, sensor_data.reading, sensor.elevation,sensor.room, sensor.system FROM sensor_data, sensor WHERE sensor.serial = sensor_data.serial AND sensor_data.dtg BETWEEN NOW() - INTERVAL 1 MINUTE AND NOW();

结果如下所示

+------------------+---------------------+---------+-----------+-------+--------+
| serial           | dtg                 | reading | elevation | room  | system |
+------------------+---------------------+---------+-----------+-------+--------+
| 2D0008017075F210 | 2013-08-02 12:34:39 |    98.6 |         5 | 2B211 | test   |
| 2D0008017075F210 | 2013-08-02 12:34:49 |    98.6 |         5 | 2B211 | test   |
| 2D0008017075F210 | 2013-08-02 12:34:59 |    98.6 |         5 | 2B211 | test   |
| 2D0008017075F210 | 2013-08-02 12:35:09 |    98.6 |         5 | 2B211 | test   |
| 2D0008017075F210 | 2013-08-02 12:35:19 |    98.6 |         5 | 2B211 | test   |
| 2D0008017075F210 | 2013-08-02 12:35:29 |    98.6 |         5 | 2B211 | test   |
| 1D00080170496D10 | 2013-08-02 12:34:39 |    73.4 |         5 | 2B211 | test   |
| 1D00080170496D10 | 2013-08-02 12:34:49 |    73.4 |         5 | 2B211 | test   |
| 1D00080170496D10 | 2013-08-02 12:34:59 |    73.4 |         5 | 2B211 | test   |
| 1D00080170496D10 | 2013-08-02 12:35:09 |    73.4 |         5 | 2B211 | test   |
| 1D00080170496D10 | 2013-08-02 12:35:19 |    73.4 |         5 | 2B211 | test   |
| 1D00080170496D10 | 2013-08-02 12:35:29 |    73.4 |         5 | 2B211 | test   |
| 380008017037ED10 | 2013-08-02 12:34:39 |    79.7 |         5 | 2B211 | test   |
| 380008017037ED10 | 2013-08-02 12:34:49 |    79.7 |         5 | 2B211 | test   |
| 380008017037ED10 | 2013-08-02 12:34:59 |    79.7 |         5 | 2B211 | test   |
| 380008017037ED10 | 2013-08-02 12:35:09 |    79.7 |         5 | 2B211 | test   |
| 380008017037ED10 | 2013-08-02 12:35:19 |    79.7 |         5 | 2B211 | test   |
| 380008017037ED10 | 2013-08-02 12:35:29 |    79.7 |         5 | 2B211 | test   |
+------------------+---------------------+---------+-----------+-------+--------+

我想要做的是创建一个声明，可以说出5天的记录，并返回每天有一行的结果集，其中包含所有上述信息以及每天的平均温度。我知道目前的数据都具有相同的温度，但是它处于一个没有任何变化的测试环境中。不是DBA我有点卡住了。

Answer 1

您需要格式化日期时间以去除时间组件，然后按其分组：

SELECT 
    sensor.serial,
    date_format(sensor_data.dtg, '%m/%Y/%d') as dtg_day,
    sensor.elevation,
    sensor.room, 
    sensor.system,
    avg(sensor_data.reading),
    count(1) reading_count
FROM 
    sensor
    NATURAL JOIN sensor_data
GROUP BY
    sensor.serial,
    dtg_day,
    sensor.elevation,
    sensor.room, 
    sensor.system

SQLFiddle here

按日期间隔按序列号分组的平均温度

1 个答案: