鉴于
template <typename...> struct Pack;
using T1 = std::tuple<int, char, double>;
using T2 = std::tuple<bool, double, int, char>;
TupleTree<Pack, T1, T2>
应为
Pack<
Pack<int, bool>, Pack<int, double>, Pack<int, int>, Pack<int, char>,
Pack<char, bool>, Pack<char, double>, Pack<char, int>, Pack<char, char>,
Pack<double, bool>, Pack<double, double>, Pack<double, int>, Pack<double, char>
>
这延伸到任意数量的元组。容易理解定义吗?好的,我让程序正常工作:
但现在我想将定义扩展到
`TupleTreeWithRepeats<P, std::index_sequence<Is...>, Tuples...>`
其中Is...
将指示每个元组重复使用的次数,直到转到下一个元组。请注意,<Is...> = <1,1,...,1>
将减少到与TupleTree<P, Tuples...>
相同。我坚持的模棱两可是这两个专业:
TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, LoopNumber, P<Ts...>, First, Rest...>
TupleTreeWithRepeatsHelper<P, std::index_sequence<I, Is...>, I, P<Ts...>, First, Rest...>
出于某种原因,P<Ts...>
的存在会导致歧义,因为当我用单一命名的类型替换它时,歧义就会消除。即使我用std::index_sequence<Is...>
替换std::index_sequence<I, Is...>
,模糊性仍然存在。这是怎么回事?以及如何解决这个问题?以下是代码,与TupleTree
几乎相同:
#include <iostream>
#include <tuple>
#include <type_traits>
template <typename T> struct Identity { using type = T; };
// Merging packs of types.
template <typename...> struct MergePacks;
template <typename Pack>
struct MergePacks<Pack> : Identity<Pack> {};
template <template <typename...> class P, typename... Types1, typename... Types2, typename... Packs>
struct MergePacks<P<Types1...>, P<Types2...>, Packs...> : MergePacks<P<Types1..., Types2...>, Packs...> {};
// Appending a type to a pack.
template <typename Pack, typename T> struct AppendType;
template <template <typename...> class P, typename... Ts, typename T>
struct AppendType <P<Ts...>, T> {
using type = P<Ts..., T>;
};
// ExpandPackWithTuple takes a pack, and creates N packs that each end with the tuple's elements, N is the size of the tuple.
template <template <typename...> class P, typename Pack, typename Tuple, typename Indices> struct ExpandPackWithTupleHelper;
template <template <typename...> class P, typename Pack, typename Tuple, std::size_t... Is>
struct ExpandPackWithTupleHelper<P, Pack, Tuple, std::index_sequence<Is...>> {
using type = P<typename AppendType<Pack, typename std::tuple_element<Is, Tuple>::type>::type...>;
};
template <template <typename...> class P, typename Pack, typename Tuple>
using ExpandPackWithTuple = typename ExpandPackWithTupleHelper<P, Pack, Tuple, std::make_index_sequence<std::tuple_size<Tuple>::value>>::type;
// TupleTreeWithRepeats.
template <template <typename...> class P, typename NumRepeats, std::size_t LoopNumber, typename OutputPack, typename... Tuples> struct TupleTreeWithRepeatsHelper;
template <template <typename...> class P, std::size_t I, std::size_t... Is, std::size_t LoopNumber, typename... Ts, typename First, typename... Rest>
struct TupleTreeWithRepeatsHelper<P, std::index_sequence<I, Is...>, LoopNumber, P<Ts...>, First, Rest...> :
TupleTreeWithRepeatsHelper<P, std::index_sequence<I, Is...>, LoopNumber + 1, typename MergePacks<ExpandPackWithTuple<P, Ts, First>...>::type, First, Rest...> {};
template <template <typename...> class P, std::size_t I, std::size_t... Is, typename... Ts, typename First, typename... Rest>
struct TupleTreeWithRepeatsHelper<P, std::index_sequence<I, Is...>, I, P<Ts...>, First, Rest...> :
TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, 0, typename MergePacks<ExpandPackWithTuple<P, Ts, First>...>::type, Rest...> {};
template <template <typename...> class P, std::size_t... Is, std::size_t LoopNumber, typename OutputPack>
struct TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, LoopNumber, OutputPack> {
using type = OutputPack;
};
template <template <typename...> class P, typename NumRepeats, typename... Tuples> struct TupleTreeWithRepeats;
template <template <typename...> class P, std::size_t I, std::size_t... Is, typename... Tuples>
struct TupleTreeWithRepeats<P, std::index_sequence<I, Is...>, Tuples...> : TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, 0, P<P<>>, Tuples...> {};
// Testing
template <typename...> struct Pack;
using T1 = std::tuple<int, char, double>;
using T2 = std::tuple<bool, double, int, char>;
using T3 = std::tuple<double, int>;
int main() {
std::cout << std::is_same<
TupleTreeWithRepeats<Pack, std::index_sequence<1,1,1>, T1, T2, T3>::type,
Pack<
Pack<int, bool, double>, Pack<int, bool, int>, Pack<int, double, double>, Pack<int, double, int>, Pack<int, int, double>, Pack<int, int, int>, Pack<int, char, double>, Pack<int, char, int>,
Pack<char, bool, double>, Pack<char, bool, int>, Pack<char, double, double>, Pack<char, double, int>, Pack<char, int, double>, Pack<char, int, int>, Pack<char, char, double>, Pack<char, char, int>,
Pack<double, bool, double>, Pack<double, bool, int>, Pack<double, double, double>, Pack<double, double, int>, Pack<double, int, double>, Pack<double, int, int>, Pack<double, char, double>, Pack<double, char, int>
>
>::value << '\n'; // ambiguous
}
答案 0 :(得分:1)
据我所知,这两者不应该含糊不清。
无论如何,一个简单的解决方法就是实现&#34;重复&#34;在&#34;没有重复&#34;:
// TupleTreeWithRepeats.
template <template <typename...> class P, typename Tuples>
struct TupleTreeWithRepeatsHelper;
template <template <typename...> class P, typename... Tuples>
struct TupleTreeWithRepeatsHelper<P, Pack<Tuples...>> :
Identity<TupleTree<P, Tuples...>> {};
template <template <typename...> class P, typename NumRepeats, typename... Tuples>
struct TupleTreeWithRepeats;
template <template <typename...> class P, std::size_t... Is, typename... Tuples>
struct TupleTreeWithRepeats<P, std::index_sequence<Is...>, Tuples...> :
TupleTreeWithRepeatsHelper<P, typename MergePacks<repeat<Tuples, Is>...>::type> {};
repeat
template<class T, std::size_t> using id = T;
template<class T, std::size_t... Is>
Pack<id<T, Is>...> do_repeat(std::index_sequence<Is...>);
template<class T, std::size_t I>
using repeat = decltype(do_repeat<T>(std::make_index_sequence<I>()));
Demo。有人可能会说这也是一个更好的设计。
最小化为:
template<class> class Purr { };
template <template <class> class, class>
struct Meow;
template <template <class> class P>
struct Meow<P, P<int>> { };
template <template <class> class P, class T>
struct Meow<P, P<T>> { };
Meow<Purr, Purr<int>> c;
GCC报告的含糊不清,这对我来说肯定是个错误。 Clang正确处理了这个问题。
答案 1 :(得分:0)
虽然T.C。的解决方案当然更优雅,但我发现这种解决方法可能是一般的解决方法,只要遇到此GCC错误就应该始终有效。我没有避免GCC的错误,而是面对它。只需将P<Ts...>
替换为单个类型名称,并定义使用它的单独元函数:
template <template <typename...> class P, typename OutputPack, typename Tuple> struct AddToOutput;
template <template <typename...> class P, typename... Ts, typename Tuple>
struct AddToOutput<P, P<Ts...>, Tuple> : MergePacks<ExpandPackWithTuple<P, Ts, Tuple>...> {};
// My workaround, using struct AddToOutput.
template <template <typename...> class P, std::size_t... Is, std::size_t LoopNumber, typename OutputPack, typename First, typename... Rest>
struct TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, LoopNumber, OutputPack, First, Rest...> :
TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, LoopNumber + 1, typename AddToOutput<P, OutputPack, First>::type, First, Rest...> {};
template <template <typename...> class P, std::size_t I, std::size_t... Is, typename OutputPack, typename First, typename... Rest>
struct TupleTreeWithRepeatsHelper<P, std::index_sequence<I, Is...>, I, OutputPack, First, Rest...> :
TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, 1, typename AddToOutput<P, OutputPack, First>::type, Rest...> {};
整个代码:
#include <iostream>
#include <tuple>
template <typename T> struct Identity { using type = T; };
// Merging packs of types.
template <typename...> struct MergePacks;
template <typename Pack>
struct MergePacks<Pack> : Identity<Pack> {};
template <template <typename...> class P, typename... Types1, typename... Types2, typename... Packs>
struct MergePacks<P<Types1...>, P<Types2...>, Packs...> : MergePacks<P<Types1..., Types2...>, Packs...> {};
// Appending a type to a pack.
template <typename Pack, typename T> struct AppendType;
template <template <typename...> class P, typename... Ts, typename T>
struct AppendType <P<Ts...>, T> {
using type = P<Ts..., T>;
};
// ExpandPackWithTuple takes a pack, and creates N packs that each end with the tuple's elements, where N is the size of the tuple.
template <template <typename...> class P, typename Pack, typename Tuple, typename Indices> struct ExpandPackWithTupleHelper;
template <template <typename...> class P, typename Pack, typename Tuple, std::size_t... Is>
struct ExpandPackWithTupleHelper<P, Pack, Tuple, std::index_sequence<Is...>> {
using type = P<typename AppendType<Pack, typename std::tuple_element<Is, Tuple>::type>::type...>;
};
template <template <typename...> class P, typename Pack, typename Tuple>
using ExpandPackWithTuple = typename ExpandPackWithTupleHelper<P, Pack, Tuple, std::make_index_sequence<std::tuple_size<Tuple>::value>>::type;
// Now, for TupleTree itself.
template <template <typename...> class P, typename OutputPack, typename... Tuples> struct TupleTreeHelper;
template <template <typename...> class P, typename... Ts, typename First, typename... Rest>
struct TupleTreeHelper<P, P<Ts...>, First, Rest...> : TupleTreeHelper<P, typename MergePacks<ExpandPackWithTuple<P, Ts, First>...>::type, Rest...> {};
template <template <typename...> class P, typename OutputPack>
struct TupleTreeHelper<P, OutputPack> {
using type = OutputPack;
};
template <template <typename...> class P, typename... Tuples>
using TupleTree = typename TupleTreeHelper<P, P<P<>>, Tuples...>::type;
// TupleTreeWithRepeats.
template <template <typename...> class P, typename NumRepeats, std::size_t LoopNumber, typename OutputPack, typename... Tuples> struct TupleTreeWithRepeatsHelper;
template <template <typename...> class P, typename OutputPack, typename Tuple> struct AddToOutput; // This is only needed for a workaround against the GCC 5.1 bug explained below.
template <template <typename...> class P, typename... Ts, typename Tuple>
struct AddToOutput<P, P<Ts...>, Tuple> : MergePacks<ExpandPackWithTuple<P, Ts, Tuple>...> {};
// The following two specializations run into ambiguity with GCC 5.1, though Clang runs it fine. It is GCC that is bugged.
//template <template <typename...> class P, std::size_t... Is, std::size_t LoopNumber, typename... Ts, typename First, typename... Rest>
//struct TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, LoopNumber, P<Ts...>, First, Rest...> :
// TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, LoopNumber + 1, typename MergePacks<ExpandPackWithTuple<P, Ts, First>...>::type, First, Rest...> {};
//
//template <template <typename...> class P, std::size_t I, std::size_t... Is, typename... Ts, typename First, typename... Rest>
//struct TupleTreeWithRepeatsHelper<P, std::index_sequence<I, Is...>, I, P<Ts...>, First, Rest...> :
// TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, 1, typename MergePacks<ExpandPackWithTuple<P, Ts, First>...>::type, Rest...> {};
// My workaround, using struct AddToOutput.
template <template <typename...> class P, std::size_t... Is, std::size_t LoopNumber, typename OutputPack, typename First, typename... Rest>
struct TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, LoopNumber, OutputPack, First, Rest...> :
TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, LoopNumber + 1, typename AddToOutput<P, OutputPack, First>::type, First, Rest...> {};
template <template <typename...> class P, std::size_t I, std::size_t... Is, typename OutputPack, typename First, typename... Rest>
struct TupleTreeWithRepeatsHelper<P, std::index_sequence<I, Is...>, I, OutputPack, First, Rest...> :
TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, 1, typename AddToOutput<P, OutputPack, First>::type, Rest...> {};
template <template <typename...> class P, typename OutputPack>
struct TupleTreeWithRepeatsHelper<P, std::index_sequence<>, 1, OutputPack> {
using type = OutputPack;
};
template <template <typename...> class P, typename NumRepeats, typename... Tuples> struct TupleTreeWithRepeats;
template <template <typename...> class P, std::size_t... Is, typename... Tuples>
struct TupleTreeWithRepeats<P, std::index_sequence<Is...>, Tuples...> : TupleTreeWithRepeatsHelper<P, std::index_sequence<Is...>, 1, P<P<>>, Tuples...> {};
// Testing
#include <type_traits>
template <typename...> struct Pack;
using T1 = std::tuple<int, char, double>;
using T2 = std::tuple<bool, double, int, char>;
using T3 = std::tuple<double, int>;
int main() {
std::cout << std::boolalpha;
std::cout << std::is_same<
ExpandPackWithTuple<Pack, Pack<int, bool>, std::tuple<int, char, double>>,
Pack<Pack<int, bool, int>, Pack<int, bool, char>, Pack<int, bool, double>>
>::value << '\n'; // true
std::cout << std::is_same<
MergePacks<ExpandPackWithTuple<Pack, Pack<>, T1>>::type,
Pack<Pack<int>, Pack<char>, Pack<double>>
>::value << '\n'; // true
std::cout << std::is_same<
MergePacks<ExpandPackWithTuple<Pack, Pack<int>, T2>, ExpandPackWithTuple<Pack, Pack<char>, T2>, ExpandPackWithTuple<Pack, Pack<double>, T2>>::type,
Pack<
Pack<int, bool>, Pack<int, double>, Pack<int, int>, Pack<int, char>,
Pack<char, bool>, Pack<char, double>, Pack<char, int>, Pack<char, char>,
Pack<double, bool>, Pack<double, double>, Pack<double, int>, Pack<double, char>
>
>::value << '\n'; // true
std::cout << std::is_same<
TupleTree<Pack, T1, T2>,
Pack<
Pack<int, bool>, Pack<int, double>, Pack<int, int>, Pack<int, char>,
Pack<char, bool>, Pack<char, double>, Pack<char, int>, Pack<char, char>,
Pack<double, bool>, Pack<double, double>, Pack<double, int>, Pack<double, char>
>
>::value << '\n'; // true
std::cout << std::is_same<
TupleTree<Pack, T1, T2, T3>,
Pack<
Pack<int, bool, double>, Pack<int, bool, int>, Pack<int, double, double>, Pack<int, double, int>, Pack<int, int, double>, Pack<int, int, int>, Pack<int, char, double>, Pack<int, char, int>,
Pack<char, bool, double>, Pack<char, bool, int>, Pack<char, double, double>, Pack<char, double, int>, Pack<char, int, double>, Pack<char, int, int>, Pack<char, char, double>, Pack<char, char, int>,
Pack<double, bool, double>, Pack<double, bool, int>, Pack<double, double, double>, Pack<double, double, int>, Pack<double, int, double>, Pack<double, int, int>, Pack<double, char, double>, Pack<double, char, int>
>
>::value << '\n'; // true
std::cout << std::is_same<
TupleTreeWithRepeats<Pack, std::index_sequence<1,1>, T1, T2>::type,
Pack<
Pack<int, bool>, Pack<int, double>, Pack<int, int>, Pack<int, char>,
Pack<char, bool>, Pack<char, double>, Pack<char, int>, Pack<char, char>,
Pack<double, bool>, Pack<double, double>, Pack<double, int>, Pack<double, char>
>
>::value << '\n'; // true
std::cout << std::is_same<
TupleTreeWithRepeats<Pack, std::index_sequence<1,1,1>, T1, T2, T3>::type,
Pack<
Pack<int, bool, double>, Pack<int, bool, int>, Pack<int, double, double>, Pack<int, double, int>, Pack<int, int, double>, Pack<int, int, int>, Pack<int, char, double>, Pack<int, char, int>,
Pack<char, bool, double>, Pack<char, bool, int>, Pack<char, double, double>, Pack<char, double, int>, Pack<char, int, double>, Pack<char, int, int>, Pack<char, char, double>, Pack<char, char, int>,
Pack<double, bool, double>, Pack<double, bool, int>, Pack<double, double, double>, Pack<double, double, int>, Pack<double, int, double>, Pack<double, int, int>, Pack<double, char, double>, Pack<double, char, int>
>
>::value << '\n'; // true
}