你如何只允许列表中的输入？ （蟒蛇自动售货机）

Question

我需要编码自动售货机，只接受某些硬币

  

“这将允许您输入1p，2p，5p，10p，20p，50p和£1.00但它将拒绝2.00英镑的硬币”

我有一个列表，其中包含浮点值：

coins = ["0.01","0.02","0.05","0.10","0.20","0.50","1"]

这些是硬币，我希望用户进入

coin = float(input())

此后我有

def balance():
     coin = float(input("Please enter your coins."))
     if coin not in coins:
            print("Incorrect coin amount! Please remember we don't accept 2 pound coins!")

     else:
        print("Correct coin amount. The coins have been added to your balance")
        fb = fb + coin

我无法让这个工作，因为它只会打印“不正确的硬币数量！请记住我们不接受2磅硬币！”。 在此之后，我在此处尝试了此解决方案：Python Coding - Vending machine - How to get the user to only enter certain coins? 我认为这意味着我需要更改我的浮点数（input（））并且所有内容都浮动到int，因此将0.01（1p）更改为1.但是，当我这样做时，我仍然得到了

'int' object has no attribute 'split'

在此代码中使用

时

dict = {"KitKat":"80p", "Coca-Cola":"85p", "DairyMilk":"80p","Walkers Crisps":"90p"}
coins = ["1","2","5","10","20","50","100"]

def balance():
    inp = int(input("Please enter your coins. Please enter in pence, for example 1 pound = 100"))
    if any(int(coin) not in value for coin in inp.split()):
        print("Machine doesn't accept these coins")


else:
    print("Correct coin amount. The coins have been added to your balance")
    fb = fb + coin


def items():
    print (" 1. KitKat:" , dict['KitKat'])
    print (" 2. Coca-Cola:", dict['Coca-Cola'])
    print (" 3. Dairy Milk:", dict["DairyMilk"])
    print (" 4. Walkers Crisps:", dict["Walkers Crisps"])
snack = 1 # need a while loop, ignore
fb = 0.00
balance()
print("Your full balance is",fb)

Answer 1

我建议将磅转换为便士，这样您就不必进行浮动数学运算，只需在显示值时转换回来。您也可以使用decimal模块，但是我们还没有太多参与其中。您的最终问题似乎是您正在比较不同类型的值，1 != "1"。让我们先排序。

coins = [1, 2, 5, 10, 20, 50, 100]  # pence
coin_in = int(input("Enter amount (in pence): "))

if coin_in not in coins:
    # incorrect input, handle it