Question

寻找MaxDate，它的最新日期和间隔。在MaxDate和最近的，我还需要每个的数量，所以我也可以找到间隔

表“tblITEM_InventoryCount”结构如下：

Item_No计数日期数量

001 08/29/2015 12

001 08/15/2015 17

001 07/15/2015 19

项目编号001

Max（CountDate）2015年8月29日

PriorCountDate 08/15/2015

间隔天数（MaxDate-RecentDate）14

MaxDate数量12

PriorCountDate数量17

区间数量（17-12）5

目前使用查询查找每个ITEM_NO的最后两个计数日期

SELECT tblITEM_InventoryCount.ITEM_NO, tblITEM_InventoryCount.Quantity, tblITEM_InventoryCount.CountDate
FROM tblITEM_InventoryCount
WHERE (((tblITEM_InventoryCount.CountDate)>=NthInGroup([tblITEM_InventoryCount].[ITEM_NO],2)))
ORDER BY tblITEM_InventoryCount.ITEM_NO, tblITEM_InventoryCount.CountDate DESC;

然后我使用第二个查询来计算我的数据：

SELECT qryLAST2_InventoryCount_TRANSACTIONS.ITEM_NO,      qryLAST2_InventoryCount_TRANSACTIONS.CountDate, (SELECT MAX([CountDate]) FROM [qryLAST2_InventoryCount_TRANSACTIONS] AS [Old Orders] WHERE [Old Orders].[CountDate] < [qryLAST2_InventoryCount_TRANSACTIONS].[CountDate] AND [Old Orders].[ITEM_NO] = [qryLAST2_InventoryCount_TRANSACTIONS].[ITEM_NO]) AS PriorCountDate, [CountDate]-[PriorCountDate] AS DaysInterval, qryLAST2_InventoryCount_TRANSACTIONS.Quantity, (SELECT Last([Quantity]) FROM [qryLAST2_InventoryCount_TRANSACTIONS] AS [OldCount] WHERE [OldCount].[Quantity] < [qryLAST2_InventoryCount_TRANSACTIONS].[Quantity] AND [OldCount].[ITEM_NO] = [qryLAST2_InventoryCount_TRANSACTIONS].[ITEM_NO]) AS PriorQuantity, [Quantity]-[PriorQuantity] AS QuantityInterval, [QuantityInterval]*30/[DaysInterval] AS [Usage]
FROM qryLAST2_InventoryCount_TRANSACTIONS
GROUP BY qryLAST2_InventoryCount_TRANSACTIONS.ITEM_NO, qryLAST2_InventoryCount_TRANSACTIONS.CountDate, qryLAST2_InventoryCount_TRANSACTIONS.Quantity
ORDER BY qryLAST2_InventoryCount_TRANSACTIONS.ITEM_NO, qryLAST2_InventoryCount_TRANSACTIONS.CountDate DESC;

我没有得到我需要的结果。查询返回每个项目的两条记录行及其最大或最后一个countdate，前一个countdate，intervaldays，qty，last qty和interval。

我需要max或last countdate及其数量计数和之前的countdate及其数量。

非常感谢任何帮助。

Answer 1

试试这个：

 select 
   tab.item_no, 
   tab.Max_Date, 
   tab.PriorCountDate, 
   DateDiff ("d", tab.Max_Date, tab.PriorCountDate) as IntervalDays,
   tab.MaxDateQty,
   tab.PriorCountDateQty,
   ( tab.MaxDateQty-tab.PriorCountDateQty) as IntervalQty,


 from

   ( select 
          temp1.item_no as item_no, 
          temp1.m as Max_Date, 
          (select MAX(count_date) from tblITEM_InventoryCount where count_date <> temp1.m ) as PriorCountDate,
          temp1.q as MaxDateQty,
          (select MAX(Qty) from tblITEM_InventoryCount where Qty <> temp1.q) as PriorCountDateQty,


     from

       ( select item_no as i, Qty as q, MAX(count_date) as m
         group by item_no, Qty ) as temp1

       inner join

          tblITEM_InventoryCount as temp2   

       on

          temp1.item_no = temp2.item_no 
    )
     as tab  ;

MS Access最大日期和最近日期及其各自的数量

1 个答案: