Question

我正在尝试编译其他人的项目。我已经设法在Windows下构建它，这意味着它可以编译，但现在我在Linux上苦苦挣扎。具体来说，我收到一个文件的错误：

#ifndef _LOGGER_H_2011_27_02_ 
#define _LOGGER_H_2011_27_02_ 

//  logger
#include <log4cplus/logger.h>
#include <iomanip>

#define LOG_TRACE(logger, msg) LOG4CPLUS_TRACE(logger, \
    "[@" << std::hex << (size_t)this << "] " << std::dec << msg);

#define LOG_DEBUG(logger, msg) LOG4CPLUS_DEBUG(logger, \
    "[@" << std::hex << (size_t)this << "] " << std::dec << msg);

// I erased repetitive declarations for WARN, FATAl etc...

代码本身对我没有意义，表达式"[@" <<有点狂野，但无关紧要，它应该编译。我得到的错误是：

source/repository/../query/../loader/../common/logger.h:30:64: error: ‘LOG4CPLUS_ERROR’ was not declared in this scope
     "[@" << std::hex << (size_t)this << "] " << std::dec << msg);

还有：

source/repository/Repository.cpp: In member function ‘void W3TTServer::Repository::cleanupSessions()’:
source/repository/Repository.cpp:82:64: error: invalid operands of types ‘const char [33]’ and ‘long int’ to binary ‘operator<<’
  LOG4CPLUS_TRACE(logger, "Cleaning up inactive sessions..." << sessionCleanupTimer);

我启用了详细模式，但这是一个笑话，实际上，我得到的只是包含目录的列表：

#include <...> search starts here:
 /usr/local/ssl/include
 /usr/include/c++/4.9
 /usr/include/x86_64-linux-gnu/c++/4.9
 /usr/include/c++/4.9/backward
 /usr/lib/gcc/x86_64-linux-gnu/4.9/include
 /usr/local/include
 /usr/lib/gcc/x86_64-linux-gnu/4.9/include-fixed
 /usr/include/x86_64-linux-gnu
 /usr/include
End of search list.

log4cplus库安装在/usr/include/log4cplus/中，由于没有关于丢失头文件的错误，我认为<log4cplus/logger.h>加载得很好。为了验证这一点，我需要一个包含文件的列表来查看位置是否正确。

如何在GCC中获取包含文件的列表？

Answer 1

将-H (preprocessor) option传递给g++，通常在Makefile添加CXXFLAGS += -H，例如Makefile。加入

make CXX='g++ -H -Wall'

在g++

的适当位置

您可以在终端上尝试-H。

如果您在终端中输入tblDataSet.Tables.Add(Table_c);，请在其后添加private DataTable Table_c; // Table_c is imported from a local database private DataTable Table_a; // Table_a is imported from a local database private DataSet tblDataSet; private void Form1_Load(object sender, EventArgs e) { this.table_aTableAdapter1.Fill(this.DBDataSet1.Table_a); this.table_cTableAdapter.Fill(this.DBDataSet1.Table_c); tblDataSet = new DataSet(); tblDataSet.Tables.Add(Table_c); tblDataSet.Tables.Add(Table_a); tblDataSet.Relations.Add("Relation1", Table_c.Columns["Number"], Table_a.Columns["Number"]); BindingSource bsC = new BindingSource(); bsC.DataSource = tblDataSet; bsC.DataMember = "Table_c"; BindingSource bsA = new BindingSource(); bsA.DataSource = bsC; bsA.DataMember = "Relation1"; table_cDataGridView.DataSource = bsC; table_aDataGridView.DataSource = bsA; }。

GCC中包含文件的更详细模式

1 个答案: