Question

您好我有一个脚本，它在数组中获取JSON输出，但我想只提取名称字段。它实际上是HostBill API，我只想打印域TLD。我尝试了所有的方法，但我收到了这个错误 注意：尝试在第22行的C：\ xampp \ htdocs \ hostbill \ check \ index.php中获取非对象的属性

我不知道代码有什么问题。

我要求的输出是：产品名称：“。com”; 这是来自这个JSON “name”：“。com”，

我的PHP代码是：

<?php
   $url = 'http://localhost/hostbill/admin/api.php';
   $post = array(
      'api_id' => '4c76ed9e1d48cc4f5d56',
      'api_key' => '2056c9b03cc95ce625b1',
      'call' => 'getProducts',
      'id'=>1
   );
   $ch = curl_init();
   curl_setopt($ch, CURLOPT_URL, $url);
   curl_setopt($ch, CURLOPT_POST, 1);
   curl_setopt($ch, CURLOPT_TIMEOUT, 30);
   curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
   curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
   curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
   curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, false);
   $data = curl_exec($ch);
   curl_close($ch);
   $return = json_decode($data, true);
   print_r($return);
   $product_name = $return->name;
   echo "Product Name: ".$product_name;
?>

Hostbill JSON响应示例：

   {
      "success": true,
      "products": {
         "236": {
            "id": "236",
            "type": "9",
            "name": "VPS-1024-w-sliders",
            "stock": "0",
            "paytype": "Free",
            "description": "",
            "m_setup": "0.00",
            "q_setup": "0.00",
            "s_setup": "0.00",
            "a_setup": "0.00",
            "b_setup": "0.00",
            "t_setup": "0.00",
            "d_setup": "0.00",
            "w_setup": "0.00",
            "h_setup": "0.00",
            "m": "30.00",
            "q": "0.00",
            "a": "0.00",
            "s": "0.00",
            "b": "0.00",
            "t": "0.00",
            "d": "0.00",
            "w": "0.00",
            "h": "0.00",
            "qty": "0",
            "visible": "1",
            "ptype": "onappcloud",
            "accounts": "1"
         },
         "235": {
            "id": "235",
            "type": "9",
            "name": "VPS-512-w-sliders",
            "stock": "0",
            "paytype": "Regular",
            "description": "",
            "m_setup": "0.00",
            "q_setup": "0.00",
            "s_setup": "0.00",
            "a_setup": "0.00",
            "b_setup": "0.00",
            "t_setup": "0.00",
            "d_setup": "0.00",
            "w_setup": "0.00",
            "h_setup": "0.00",
            "m": "20.00",
            "q": "0.00",
            "a": "0.00",
            "s": "0.00",
            "b": "0.00",
            "t": "0.00",
            "d": "0.00",
            "w": "0.00",
            "h": "0.00",
            "qty": "0",
            "visible": "1",
            "ptype": "onappcloud",
            "accounts": "3"
         }
      },
      "call": "getProducts",
      "server_time": 1317712858
   }

Answer 1

产品位于array，因此请使用foreach来迭代所有产品。

foreach($return['products'] AS $product){
    echo "Product Name: ".$product['name'];
}

您还应该检查API响应是否有效。如果API不响应产品数组或响应空响应，则会出现错误。这样就可以了。

if(isset($return['products']) && is_array($return['products'])){
    foreach($return['products'] AS $product){
        echo "Product Name: ".$product['name'];
    }
}

仅提取特定类别

要仅获取某些产品，请使用if语句。例如，从category_id 1和type 9获取产品：

foreach($return['products'] AS $product){
    if($product['category_id'] == 1 && $product['type'] == 9){
        echo "Product Name: ".$product['name'];
    }
}

Answer 2

您将收到该错误，因为它不是对象。这是一个数组。

所以它应该是：

 foreach($return['products'] as $key => $product){
  echo "Product Name: ".  $product['name'];
 }

从JSON

2 个答案: