Question

我创建了一个API

这是URL http://geoip.mediaciptainformasi.co.id/ip.php?ip=1.1.1.1 并且输出像{<1}}一样响应

json

如何获取特定键值，例如其他网站的{ "ip_address": "1.1.1.1", "Jumlah Akses per hari": "1 kali", "ip_from": "16843008", "ip_to": "16843263", "country_code": "AU", "country_name": "Australia", "region_name": "Queensland", "city_name": "Brisbane", "latitude": "-27.46794", "longitude": "153.02809", "zip_code": "4000", "time_zone": "+10:00" }和country_name？

我已在city_name上尝试了此操作，但无法正常工作

localhost

Answer 1

使用cURL：

<?php
// when you want to display errors by overriding `php.ini`
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);

// function to return cURL response
function get_data_function($ip)
{
    if ($ip == NULL){
        $ip = "1.1.1.1";
    }
    // base url
    $url = "http://geoip.mediaciptainformasi.co.id/ip.php/?ip=".$ip;

    $ch = curl_init($url);
    // cURL OPTIONS: 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

    $result = curl_exec($ch);

    // Check for errors and display the error message
    if($errno = curl_errno($ch)) {
        $error_message = curl_strerror($errno);
        echo "cURL error ({$errno}):\n {$error_message}";
    }

    if (isset($result)) {
        $response = json_decode($result, true);
    }
    curl_close($ch);

    return $response;
}

    // calling method with desired IP string
    $response =  get_data_function("110.138.84.204");

    // get specific value by its json key
    echo "Country Name " . $response['country_name'];
    echo "</br>";
    echo "City Name " . $response['city_name'];

    echo "</br>";
    echo "</br>";

    // in case of view full response
    var_dump($response);
?>

在localhost

上正常工作

Answer 2

$url = "http://geoip.mediaciptainformasi.co.id/ip.php/?ip=110.138.84.204";
$jsondata = file_get_contents($url);
$obj = json_decode($jsondata);
// Use this to see object, after that you can do what you want to $obj
print_r($obj);

从GET URL中提取json响应中特定键的值

2 个答案: