Question

我是java编程的新手，并尝试编写一个对Arrays进行排序的函数。我知道我的代码对于这么简单的任务来说非常强大，但它是我考虑排序的第一种方式，所以我就去了。我的逻辑是采用一个数组，用所有0做一个相同长度的数组。然后使用for循环查找未排序数组的最小值，将其放在新数组的开头，然后用未排序数组的最大值替换未排序数组的min，直到整个数组全部为maxes并且I＆＃ 39; ve填充要排序的数组。我将在下面举几个例子，因为它有点难以解释：

  -Starting Array:[2, 3, 1, 4]
  -1st Execution: [2, 3, 1, 4] [0, 0, 0, 0]
  -2nd:           [2, 3, 4, 4] [1, 0, 0, 0]
  -3rd:           [4, 3, 4, 4] [1, 2, 0, 0]
  -4th:           [4, 4, 4, 4] [1, 2, 3, 0]
  -5th:           [4, 4, 4, 4] [1, 2, 3, 4]

我编写的代码返回数组的min，找到min的索引，并返回数组的最大值。我的方法是继续这个过程，并保持一个计数器，即for循环找到min的时间，然后当它等于数组长度-1时停止。我在上一个方法中遇到了问题 - sortMe - 因为我的回复没有编译，错误是：

Error: incompatible types
found   : int[]
required: java.util.Arrays

我附上了以下所有代码：

import java.util.Arrays;

public class Homework4 {
  public static void main (String[] args) {
    int[] a = {20,2,5};
    System.out.println(Homework4.minArray(a));
    System.out.println(Homework4.maxArray(a));
    System.out.println(Homework4.minIndex(a));
    System.out.println( Arrays.toString(a));
  }
   /* 1 This method will mimic the sort methond for Arrays
    * It will be called sortMe and will take in an array and produce a sorted array
    *   In order to do this I will also create two methods: min and max
    * The numbers in the array will be of type Int
    * Homework4.sortMe([0 , 3, 4, 2, 1, 7]) -> [0 , 1, 2, 3, 4, 7]
    * Homework4.sortMe([0]) -> [0]
    * Homework4.sortMe([3, 8, 2, 14, 1)] -> [1, 2, 3, 8, 14]
    * Template:*/   
  public static int minArray (int[] x)  {                  //Produces the Minimum of an Array
    int minVal = x[0];
    for (int i = 0; i < (x.length - 1); i = i + 1) {
      if( x[i] < minVal) {
        minVal = x[i];}
    }
    return minVal;}
 public static int minIndex (int[] x)  {                  //Returns the index of the Minimum
    int minVal = x[0];
    int index  = 0;
    for (int i = 0; i < (x.length - 1); i = i + 1) {
      if( x[i] < minVal) {
        minVal = x[i];
        index = i;}
    }
    return index;}

  public static int maxArray (int[] x)  {                 //Produces the Maximum of an Array
    int maxVal = x[0];
    for (int i = 0; i < (x.length - 1); i = i + 1) {
      if( x[i] > maxVal) {
        maxVal = x[i];}
    }
    return maxVal;}

    public static Arrays sortMe (int[] x) {    //Sorts an Array
    int[] sortedArray = new int [x.length];
     int minIterations = 0;
      while (minIterations < x.length-1) {
      for(int i = 0; i < x.length-1; i = i +1){
        sortedArray[i] = Homework4.minArray(x);
        x[Homework4.minIndex(x)] = Homework4.maxArray(x);
        minIterations++;
        }}
       return sortedArray; }       
}

谢谢！

Answer 1

我想你要返回一个整数数组吗？我假设你已经将sortedArray声明为一个整数数组。

在这种情况下，方法头需要返回类型为整数数组，与使用整数数组作为参数相同：

所以：

  public static Arrays sortMe (int[] x)

变为：

  public static int[] sortMe (int[] x)

Answer 2

public static Arrays sortMe (int[] x) {...}

应该是：

public static int[] sortMe (int[] x) {...}

Answer 3

将返回类型更改为int []而不是Araays。

@Configuration

在Java中为Arrays编写排序函数并卡住

3 个答案: