Question

我对如何解析这个JSON很困惑。到目前为止，这是我的方法。另请告诉我在Android中解析JSON的正确方法

JSON:

{  
 "latitude":37.8267,
 "longitude":-122.423,
 "timezone":"America/Los_Angeles",
 "offset":-7,
 "currently":{  
  "time":1443322196,
  "summary":"Partly Cloudy",
  "icon":"partly-cloudy-night",
  "nearestStormDistance":13,
  "nearestStormBearing":77,
  "precipIntensity":0,
  "precipProbability":0,
  "temperature":63.94,
  "apparentTemperature":63.94,
  "dewPoint":55.46,
  "humidity":0.74,
  "windSpeed":8.59,
  "windBearing":277,
  "visibility":8.51,
  "cloudCover":0.44,
  "pressure":1010.39,
  "ozone":261.48
 },
  "minutely":{  
   "summary":"Partly cloudy for the hour.",
  "icon":"partly-cloudy-night",
  "data":[  
     {  
        "time":1443322140,
        "precipIntensity":0,
        "precipProbability":0
     },
 }

现在正在解析“当前”对象，但是当我尝试解析“微小”对象时，它在Logcat中没有显示任何值

这是我的代码：

JSONObject forecast = new JSONObject(jsonData);
    JSONArray summary = new JSONArray(jsonData);

    String timezone = forecast.getString("timezone");
    String city = getLocationName(forecast.getDouble("latitude"), forecast.getDouble("longitude"));

    JSONObject currently = forecast.getJSONObject("currently");
    JSONArray hour = summary.getJSONArray("minutely");
    for (int i = 0; i < hour.length(); i++) {
        JSONObject jsonObject = hour.getJSONObject(i);
        String summary = jsonObject.getString("summary");
    }
    CurrentWeather currentWeather = new CurrentWeather();
    currentWeather.setHumidity(currently.getDouble("humidity"));
    currentWeather.setTime(currently.getLong("time"));
    currentWeather.setIcon(currently.getString("icon"));
    currentWeather.setPrecipChance(currently.getDouble("precipProbability"));
    currentWeather.setTemp(currently.getDouble("temperature"));
    currentWeather.setTimezone(timezone);
    currentWeather.setLocation(city);

Answer 1

根据您在评论中添加的端点网址的响应，解析将如下所示

JSONObject forecast = new JSONObject(jsonData);

double latitude = forecast.getDouble("latitude");
double longitude= forecast.getDouble("longitude");
String timezone = forecast.getString("timezone");

JSONObject jsonObjCurrently= forecast.getJSONObject("currently");
//parse string, long and double objects within jsonObjCurrently accordingly

JSONObject jsonObjMinutely= forecast.getJSONObject("minutely");
String summary= jsonObjMinutely.getString("summary");
String icon= jsonObjMinutely.getString("icon");
JSONArray jsonArrayMinutelyData = jsonObjMinutely.getJSONArray("data");
for(int i=0; i<jsonArrayMinutelyData .length(); i++){
   JSONObject tempData = jsonArrayMinutelyData.get(i);
   long time = tempData.getLong("time");
   //parse the remaining object pairs.
}

JSONObject jsonObjHourly= forecast.getJSONObject("hourly");
//similar to minutely parsing. Only has more and different data 
JSONObject jsonObjDaily= forecast.getJSONObject("daily");
//similar to hourly parsing.
JSONObject jsonObjFlags= forecast.getJSONObject("flags");
//It has 5 array and 1 string object so parse accordingly.

我添加了解析逻辑，请相应保存数据并使用它。

Answer 2

您可以在错误的路径上解析minutely。见下面的代码（测试过）。

    try {
        // jsonString from https://api.forecast.io/forecast/8162461ea194cb97c80209d6edf4df94/37.8267,-122.423
        String jsonString = "";
        JSONObject jsonObject = new JSONObject(jsonString);
        JSONObject minutely = jsonObject.getJSONObject("minutely");
        Log.d("JSON", "minutely: " + minutely);
        String summary = minutely.getString("summary");
        Log.d("JSON", "summary: " + summary);

        JSONArray datas = minutely.getJSONArray("data");
        for (int i = 0; i < datas.length(); i++) {
            JSONObject data = datas.getJSONObject(i);
            Log.d("JSON", "data @ index" + i + ": " + data);
        }
    } catch (JSONException e) {
        e.printStackTrace();
    }

输出：

    D/JSON    ( 1590): minutely: {"summary":"Partly cloudy for the hour.","icon":"partly-cloudy-night","data":....
    D/JSON    ( 1590): summary: Partly cloudy for the hour.
    D/JSON    ( 1590): data @ index0: {"time":1443331140,"precipIntensity":0,"precipProbability":0}
    D/JSON    ( 1590): data @ index1: {"time":1443331200,"precipIntensity":0,"precipProbability":0}
    ....

Answer 3

这不是一个有效的json。您可以检查logcat是否抛出异常。如果已捕获异常，请尝试并打印堆栈跟踪。这将帮助您了解问题所在。

Answer 4

我再次检查你的json，它应该是两种情况之一第一个就像是

{  
 "latitude":37.8267,
 "longitude":-122.423,
 "timezone":"America/Los_Angeles",
 "offset":-7,
 "currently":{  
  "time":1443322196,
  "summary":"Partly Cloudy",
  "icon":"partly-cloudy-night",
  "nearestStormDistance":13,
  "nearestStormBearing":77,
  "precipIntensity":0,
  "precipProbability":0,
  "temperature":63.94,
  "apparentTemperature":63.94,
  "dewPoint":55.46,
  "humidity":0.74,
  "windSpeed":8.59,
  "windBearing":277,
  "visibility":8.51,
  "cloudCover":0.44,
  "pressure":1010.39,
  "ozone":261.48
 },
  "minutely":{  
   "summary":"Partly cloudy for the hour.",
  "icon":"partly-cloudy-night",
  "data":[  
     {  
        "time":1443322140,
        "precipIntensity":0,
        "precipProbability":0
     },
 }

并且解决方案看起来像。

JSONObject minutely = forecast.getJSONObject("minutely");

它喜欢

[
    {
        "latitude": 37.8267,
        "longitude": -122.423,
        "timezone": "America/Los_Angeles",
        "offset": -7,
        "currently": {
            "time": 1443322196,
            "summary": "Partly Cloudy",
            "icon": "partly-cloudy-night",
            "nearestStormDistance": 13,
            "nearestStormBearing": 77,
            "precipIntensity": 0,
            "precipProbability": 0,
            "temperature": 63.94,
            "apparentTemperature": 63.94,
            "dewPoint": 55.46,
            "humidity": 0.74,
            "windSpeed": 8.59,
            "windBearing": 277,
            "visibility": 8.51,
            "cloudCover": 0.44,
            "pressure": 1010.39,
            "ozone": 261.48
        },
        "minutely": {
            "summary": "Partly cloudy for the hour.",
            "icon": "partly-cloudy-night",
            "data": [
                {
                    "time": 1443322140,
                    "precipIntensity": 0,
                    "precipProbability": 0
                }
            ]
        }
    }
]

并且解决方案是您应该将预测对象更改为JsonArray。

您可以测试json here

的验证

Answer 5

分钟不是JSONArray它的JSONObject。试试这个： -

JSONObject forecast = new JSONObject(jsonData);
JSONObject jsonObjMinutely= forecast.getJSONObject("minutely");
String summary = jsonObjMinutely.getString("summary");

Answer 6

你的JSON真是无效..

让我们来看看那个更接近的人：

"minutely":{  
  "summary":"Partly cloudy for the hour.",
  "icon":"partly-cloudy-night",
  "data":[  
  {  
    "time":1443322140,
    "precipIntensity":0,
    "precipProbability":0
  },

它没有微小的JSONObject和数据的JSONArray的结束括号。另外，它有一个逗号，其中“data”数组实际上包含一个元素。

将其修复为：

"minutely":{  
  "summary":"Partly cloudy for the hour.",
  "icon":"partly-cloudy-night",
  "data":[  
  {  
    "time":1443322140,
    "precipIntensity":0,
    "precipProbability":0
  } ]
}

然后你的“微小”物体现在有效。这是第一次。

然后得到你的“微小”

...
JSONObject forecast = new JSONObject(jsonData);
JSONObject minutely = forecast.getJSONObject("minutely");

Answer 7

使用android studio解析json非常简单。在android studio安装插件GSON然后创建模型类并输入＆＃39; alt + insert＆＃39;它将为生成器弹出，然后选择GSONFormat并粘贴你的json，你将得到你的json的模型类。在您获得json响应的活动中执行此操作

Gson gson = new Gson();
YourModelClass object = gson.fromJson(jsonResponseObject.toString(), YourModelClass.class);

在这里你成功解析了json。现在是时候使用您的模型类来获取您想要的数据了

Answer 8

请编辑您的代码，如下所示

JSONObject currently = forecast.getJSONObject("currently");
Double humidity = currently.getDouble("humidity");
Long time = currently.getLong("time");
String icon = currently.getString("icon");
Double precipChance = currently.getDouble("precipProbability");
Double temp = currently.getDouble("temperature");
String timezone = forecast.getString("timezone");
JSONObject minutely = forecast.getJSONObject("minutely");

请查看以下链接，了解Json Parsing的完整示例

https://www.dropbox.com/s/q6cjifccbbw9nl1/JsonParsing.zip?dl=0

在Android中解析多个JSON对象

8 个答案: