Question

希望获得一些帮助将QuickBlox应用到我们的iOS应用程序中。我们似乎无法解决发送消息后的问题QuickBlox返回当计时器ticks事件调用块时先前已发送的所有消息。任何帮助将不胜感激！

    QBResponsePage *page = [QBResponsePage responsePageWithLimit:10 skip:0];

    [QBRequest dialogsForPage:page extendedRequest:nil successBlock:^(QBResponse *response, NSArray *dialogObjects, NSSet *dialogsUsersIDs, QBResponsePage *page)
    {
        QBChatDialog *dialog=[dialogObjects objectAtIndex:0];
        [QBRequest messagesWithDialogID:dialog.ID extendedRequest:nil forPage:page successBlock:^(QBResponse *response, NSArray *messages, QBResponsePage *responsePage)
         {
             [self.items removeAllObjects];
             [self.items addObjectsFromArray:messages];
             [self finishSendingMessageAnimated:YES];

         } errorBlock:^(QBResponse *response) {
             NSLog(@"error: %@", response.error);
         }];


    } errorBlock:^(QBResponse *response) {

    }];

以下是我们采取的步骤： 1）将所有QuickBlox类导入到我们的项目中。

2）在My App Delegate Class中设置QuickBlox的所有凭据

[QBApplication sharedApplication].applicationId = (removed);
[QBConnection registerServiceKey:@“(removed)”];
[QBConnection registerServiceSecret:@“(removed)”];
[QBSettings setAccountKey:@“(removed)”];

3）然后创建了导入的QMChatViewController的子类

4）导入NMPaginatorDelegate和Cretae UsersPaginator对象，（给我用户列表）

5）点击特定用户调用我们创建的子类，并在其viewDidLoad上面写下代码：

QBUUser *currentUser = [QBUUser user];
currentUser.ID = LoginUser.ID;
currentUser.password = LoginUser.login;

[[QBChat instance] addDelegate:(id)self];
[[QBChat instance] loginWithUser:currentUser];

在loginWithUser调用

之后

    BOOL chlLogion =[[QBChat instance]isLoggedIn];
    NSLog(@"Loggin IN Status :- %hhd”,chlLogion);

Log Print： - 2015-09-22 16：04：31.911 AppName [2263：96572] [ChatService]连接到聊天，主持人：chat.quickblox.com，用户JID：5434136-28329@chat.quickblox.com / 7DE2CD1E-481F-4922-B21D-8EB14BF8B55F 2015-09-22 16：04：42.978 AppName [2263：96225]登录状态： - 0

注意： - 堕落

 [[QBChat instance] sendMessage:message];

该代码已被删除，并且您的sdks显示了它的选项，但这也是无效的。

并设置其委托方法。

（无效）chatDidConnect { }
（无效）chatDidAccidentallyDisconnect { }
（无效）chatDidReconnect { }
（void）chatDidReceiveMessage：（QBChatMessage *）message { NSLog（@＆＃34;收到消息％@＆＃34;，消息）; }
（void）chatDidNotSendMessage：（QBChatMessage *）消息错误：（NSError *）error { }
（void）chatDidDeliverMessageWithID：（NSString *）messageID { }

然而，在没有调用另一个委托之后，它只调用了1个委托“chatDidConnect”。在发送消息我正在设置：

    QBChatDialog *chatDialog = [[QBChatDialog alloc]initWithDialogID:[NSString stringWithFormat:@"%lu",(unsigned long)LoginUser.ID] type:QBChatDialogTypePrivate];
    chatDialog.occupantIDs=@[@(SelectedChatUser.ID)];
    chatDialog.name = @"school friends";

    [QBRequest createDialog:chatDialog successBlock:^(QBResponse *response, QBChatDialog *createdDialog) {

        _dialog=createdDialog;
        QBChatMessage *message = [QBChatMessage message];

        message.text = text;
        message.senderID = senderId;
        message.recipientID=createdDialog.recipientID;
        message.deliveredIDs=[createdDialog.occupantIDs objectAtIndex:1];
        message.dialogID=[NSString stringWithFormat:@"%@",createdDialog.ID];
        message.senderNick=@"Nick Simulator";
        message.dateSent = [NSDate date];

        [self.items addObject:message];

        [createdDialog sendMessage:message];
        [self finishSendingMessageAnimated:YES];

    } errorBlock:^(QBResponse *response) {

    }];

但是发送的代码消息没有被发送，我们也没有得到任何代表的消息。

6）之后我切换到新方法发送消息。写下以下代码发送消息：

    - (void)didPressSendButton:(UIButton *)button
       withMessageText:(NSString *)text
              senderId:(NSUInteger)senderId
     senderDisplayName:(NSString *)senderDisplayName
                  date:(NSDate *)date {

QBChatDialog *chatDialog = [[QBChatDialog alloc]initWithDialogID:[NSString stringWithFormat:@"%lu",(unsigned long)LoginUser.ID] type:QBChatDialogTypePrivate];
    chatDialog.occupantIDs=@[@(SelectedChatUser.ID)];
    chatDialog.name = @"school friends";
         [QBRequest createDialog:chatDialog successBlock:^(QBResponse *response, QBChatDialog *createdDialog) {

        _dialog=createdDialog;
        QBChatMessage *message = [QBChatMessage message];

        message.text = text;
        message.senderID = senderId;
        message.recipientID=createdDialog.recipientID;
        message.deliveredIDs=[createdDialog.occupantIDs objectAtIndex:1];
        message.dialogID=[NSString stringWithFormat:@"%@",createdDialog.ID];
        message.senderNick=@"Nick Simulator";
        message.dateSent = [NSDate date];

        [self.items addObject:message];

        [QBRequest createMessage:message successBlock:^(QBResponse *response, QBChatMessage *createdMessage) {
            NSLog(@"success: %@", createdMessage);
        } errorBlock:^(QBResponse *response) {
            NSLog(@"ERROR: %@", response.error);
        }];
     [self finishSendingMessageAnimated:YES];

      } errorBlock:^(QBResponse *response) {

     }];

Answer 1

QBResponsePage的dialogsForpage将返回之前的所有消息。因此，跳过您已有的消息计数将只返回最新消息。

let page = QBResponsePage.(limit:10, skip: message count that you already have)
let parameters = ["sort_desc" : "date_sent"]
QBRequest.messagesWithDialogID(currentDialog.ID!, 
                               extendedRequest: parameters,
                               forPage: resPage, 
                               successBlock:{ (response: QBResponse, messages: [QBChatMessage]?, page: QBResponsePage?) -> Void in
                               /**your code**/
                               }

发送消息QuickBlox后，它返回先前发送的所有消息

1 个答案: