Question

在以下示例中，我如何直接从$("#guessButton").click(function(e) { e.preventDefault(); counter++; $('#count').text(counter); var guess = $('#userGuess').val(); if (guess == number) { $('#feedback').text("You've guessed the number!!"); $('#guessList').append("<li>"+guess+"</li>"); } else if (Math.abs(number-guess) <= 50 && Math.abs(number-guess) >= 30) { $('#feedback').text("Cold"); $('#guessList').append("<li>"+guess+"</li>"); } else if (Math.abs(number-guess) <= 30 && Math.abs(number-guess) >= 20) { $('#feedback').text("Warm"); $('#guessList').append("<li>"+guess+"</li>"); } else if (Math.abs(number-guess) <= 20 && Math.abs(number-guess) >= 10) { $('#feedback').text("Hot"); $('#guessList').append("<li>"+guess+"</li>"); } else if (Math.abs(number-guess) <= 10 && Math.abs(number-guess) >= 1) { $('#feedback').text("Very Hot"); $('#guessList').append("<li>"+guess+"</li>"); } else if (Math.abs(number-guess) > 50) { $('#feedback').text("Ice Cold"); $('#guessList').append("<li>"+guess+"</li>"); } });致电Base.foo()，我理解为什么它首先调用Base.bar()，但有没有办法阻止这种情况。

Test.foo()

输出将是：

class Base {
   constructor() {
      console.log('Base constructor')
   }

   foo() {
      console.log('Base foo')
   }

   bar() {
     console.log('Base bar')

     this.foo();
  }
}

class Test extends Base {
  foo() {
    console.log('Test foo');

    super.foo();
  }
  bar() {
    console.log('Test bar');

    super.bar();
  }
}

const test = new Test();
test.bar();

我的预期输出是：

Base constructor
Test bar
Base bar
Test foo
Base foo

Answer 1

使用ES2015课程时，您可以使用标准JavaScript功能。在这种情况下，只需使用Function.prototype.call()：

＆＃13;

'use strict'
class Base {
   constructor() {
      console.log('Base constructor')
   }

   foo() {
      console.log('Base foo')
   }

   bar() {
     console.log('Base bar')

     Base.prototype.foo.call(this);
  }
}

class Test extends Base {
  foo() {
    console.log('Test foo');

    super.foo();
  }
  bar() {
    console.log('Test bar');

    super.bar();
  }
}

const test = new Test();
test.bar();

＆＃13;

如何调用基类方法而不是扩展类方法

1 个答案: