所以我已经完成了(我认为)Java中的wc程序,它从用户输入(甚至是多个)中获取文件名,并对文件中的行,单词,字节(字符数)进行计数。提供了2个用于测试目的的文件,它们采用.dat格式,可从dos / linux命令行读取。除了在行尾有\ n或\ r \ n字符的计数外,一切都正常工作。它不会算这些。请帮帮忙?
import java.io.*;
import java.util.regex.Pattern;
public class Prog03 {
private static int totalWords = 0, currentWords = 0;
private static int totalLines =0, currentLines = 0;
private static int totalBytes = 0, currentBytes = 0;
public static void main(String[] args) {
System.out.println("This program determines the quantity of lines, words, and bytes\n" +
"in a file or files that you specify.\n" +
"\nPlease enter one or more file names, comma-separated: ");
getFileName();
System.out.println();
} // End of main method.
public static void countSingle (String fileName, BufferedReader in) {
try {
String line;
String[] words;
//int totalWords = 0;
int totalWords1 = 0;
int lines = 0;
int chars = 0;
while ((line = in.readLine()) != null) {
lines++;
currentLines = lines;
chars += line.length();
currentBytes = chars;
words = line.split(" ");
totalWords1 += countWords(line);
currentWords = totalWords1;
} // End of while loop.
System.out.println(currentLines + "\t\t" + currentWords + "\t\t" + currentBytes + "\t\t"
+ fileName);
} catch (Exception ex) {
ex.printStackTrace();
}
}
public static void countMultiple(String fileName, BufferedReader in) {
try {
String line;
String[] words;
int totalWords1 = 0;
int lines = 0;
int chars = 0;
while ((line = in.readLine()) != null) {
lines++;
currentLines = lines;
chars += line.length();
currentBytes = chars;
words = line.split(" ");
totalWords1 += countWords(line);
currentWords = totalWords1;
} // End of while loop.
totalLines += currentLines;
totalBytes += currentBytes;
totalWords += totalWords1;
} catch (Exception ex) {
ex.printStackTrace();
}
} // End of method count().
private static long countWords(String line) {
long numWords = 0;
int index = 0;
boolean prevWhitespace = true;
while (index < line.length()) {
char c = line.charAt(index++);
boolean currWhitespace = Character.isWhitespace(c);
if (prevWhitespace && !currWhitespace) {
numWords++;
}
prevWhitespace = currWhitespace;
}
return numWords;
} // End of method countWords().
private static void getFileName() {
BufferedReader in ;
try {
in = new BufferedReader(new InputStreamReader(System.in));
String fileName = in.readLine();
String [] files = fileName.split(", ");
System.out.println("Lines\t\tWords\t\tBytes" +
"\n--------\t--------\t--------");
for (int i = 0; i < files.length; i++) {
FileReader fileReader = new FileReader(files[i]);
in = new BufferedReader(fileReader);
if (files.length == 1) {
countSingle(files[0], in);
in.close();
}
else {
countMultiple(files[i], in);
System.out.println(currentLines + "\t\t" +
currentWords + "\t\t" + currentBytes + "\t\t"
+ files[i]);
in.close();
}
}
if (files.length > 1) {
System.out.println("----------------------------------------" +
"\n" + totalLines + "\t\t" + totalWords + "\t\t" + totalBytes + "\t\tTotals");
}
}
catch (FileNotFoundException ioe) {
System.out.println("The specified file was not found. Please recheck "
+ "the spelling and try again.");
ioe.printStackTrace();
}
catch (IOException ioe) {
ioe.printStackTrace();
}
}
} // End of class
这是整个程序,如果有人帮忙应该看到任何东西,但是这是我计算一行中每个字符串的长度的地方(我假设eol字符将是这个计数的一部分,但它们不是& #39; t)的
public static void countMultiple(String fileName, BufferedReader in) {
try {
String line;
String[] words;
int totalWords1 = 0;
int lines = 0;
int chars = 0;
while ((line = in.readLine()) != null) {
lines++;
currentLines = lines;
**chars += line.length();**
currentBytes = chars;
words = line.split(" ");
totalWords1 += countWords(line);
currentWords = totalWords1;
} // End of while loop.
totalLines += currentLines;
totalBytes += currentBytes;
totalWords += totalWords1;
} catch (Exception ex) {
ex.printStackTrace();
}
}
答案 0 :(得分:0)
BufferedReader始终忽略换行或换行符。使用readLine()无法做到这一点。
您可以改用read()方法。但在这种情况下,你必须单独阅读每个角色。
答案 1 :(得分:0)
只是评论,将一行分为单词,仅基于单个空格进行拆分是不够的:line.split(" ");
如果单词之间有多个空格或制表符,您将会错过。最好在任何空白字符line.split("\\s+");