我不知道我的问题是否有意义,但我正面临这个问题
案例1:
For i = 1 to n
strDate = workbooks.worksheet("Sheet1").cells(i,1)
emailList = workbooks.worksheet("Sheet1").cells(i,2)
if (strDate=expectedDate) then
call sendMail(emailList)
end if
Next
Public function sendMail(emailList)
Dim OutApp As Object
Dim OutMail As Object
With Application
.ScreenUpdating = False
.EnableEvents = False
End With
On Error GoTo err
'Now open a new mail
Set OutApp = CreateObject("Outlook.Application")
Set OutMail = OutApp.CreateItem(0)
On Error Resume Next
With OutMail
.To = emailList
.CC = ""
.Subject = "test"
.Body = "the content of the mail"
End With
On Error GoTo 0
'set nothing to the objects created
Set OutMail = Nothing
Set OutApp = Nothing
'Now set the application properties back to true
With Application
.ScreenUpdating = True
.EnableEvents = True
End With
MsgBox ("Email has been Sent Successfully")
Exit Sub
err:
MsgBox err.Description
End function
案例2:
String fileLine ="->->->6";
System.out.println(fileLine.split("\t").length);
output: 4
问题案例:
String fileLine ="1->->->6";
System.out.println(fileLine.split("\t").length);
output: 4
任何人都可以告诉我为什么会这样,并抓住这种情况?
即使文件结尾为空,我也希望捕获行尾的标签
由于