我正在尝试使用function_score中定义的不同函数修改普通查询的分数。
为了找出我的函数计算出的分数,我指定" boost_mode"到"替换"。但是,这会使所有分数保持不变:全部等于1.
请考虑以下查询:
{
"query": {
"function_score": {
"query": {
"terms": {
"name": ["men", "women"]
}
},
"score_mode": "avg",
"functions": [
{
"filter": {
"terms": {
"name": ["men","man"]
}
},
"weight": 2
}
],
"boost_mode": "replace"
}
},
"explain": true,
"from": 0
}
我希望在这里获得不同的分数,这取决于" name"字段包含" men"或者"男人"。这些文件肯定存在于索引中。
此外,如果我指定"解释":是的,我在解释中显示的分数与命中的_score字段中显示的分数不同:
{
"_shard":0,
"_node":"ro26nlDuTfiTaIlIgHqg4g",
"_index":"products10",
"_type":"product_basic",
"_id":"0c25fc90433481aac0cce62dd1a21e06",
"_score":1,
"_source":{
"category":[
"Chicago Blues",
"Blues",
"Styles",
"Digital Music"
],
"site_name":"www.amazon.com",
"name":"Who's That Women?",
"url":"http://www.amazon.com/dp/B001125F8I/",
"price":0.99,
"reviews":[
],
"breadcrumb":"Digital Music",
"in_stock":true,
"features":[
],
"pic_urls":[
"http://ecx.images-amazon.com/images/I/51CvgPMwtsL.jpg",
"http://ecx.images-amazon.com/images/I/51CvgPMwtsL.jpg"
],
"name_semantic_core":[
"Women ?",
"?"
],
"category_path":"/Chicago Blues/Blues/Styles/",
"visit_datetime":"2014-11-04T11:50:34.169779",
"detected_category":"Digital Music"
},
"_explanation":{
"value":1.2249949,
"description":"function score, no filter match, product of:",
"details":[
{
"value":1.2249949,
"description":"product of:",
"details":[
{
"value":2.4499898,
"description":"sum of:",
"details":[
{
"value":2.4499898,
"description":"weight(name:women in 6181332) [PerFieldSimilarity], result of:",
"details":[
{
"value":2.4499898,
"description":"score(doc=6181332,freq=1.0), product of:",
"details":[
{
"value":0.67790973,
"description":"queryWeight, product of:",
"details":[
{
"value":7.228071,
"description":"idf(docFreq=238699, maxDocs=120967660)"
},
{
"value":0.09378847,
"description":"queryNorm"
}
]
},
{
"value":3.6140356,
"description":"fieldWeight in 6181332, product of:",
"details":[
{
"value":1,
"description":"tf(freq=1.0), with freq of:",
"details":[
{
"value":1,
"description":"termFreq=1.0"
}
]
},
{
"value":7.228071,
"description":"idf(docFreq=238699, maxDocs=120967660)"
},
{
"value":0.5,
"description":"fieldNorm(doc=6181332)"
}
]
}
]
}
]
}
]
},
{
"value":0.5,
"description":"coord(1/2)"
}
]
},
{
"value":1,
"description":"queryBoost"
}
]
}
}
这里的解释显示"值":1.2249949,而" _score"是1。
我做错了什么?如何使用functinon_score函数[在与原始查询分数结合之前]计算实际分数?
答案 0 :(得分:2)
在您的示例中,该功能不匹配任何文档:function score, no filter match,
。此外,在使用替换时documentation,会发生以下情况:only function score is used, the query score is ignored
。因此,情况是这样的:过滤器不匹配 - 因此不计算得分 - 而replace
将使得查询得分被忽略并使用过滤器的得分(不会过滤) ; t存在,因为它没有匹配)。
当函数不匹配时,函数的默认值为1
。您可以使用"boost_mode": "sum"
进行检查。我的观点是,这就是你看到1
得分的原因。
关于avg
行为,这对我来说并不合适,而且很可能是一个错误。我在这里报告了它:https://github.com/elastic/elasticsearch/issues/13732