如何从char数组中删除中间元素并仅使用指针调整数组大小？

Question

标题基本上都说明了。

我需要从char数组中删除中间元素。

然后我需要在仅使用指针的情况下调整它的大小。

我不能在创建静态数组和动态新数组declerations之外使用任何数组或[]括号，例如int *temp = new int[6];

这是我目前的代码

#include <iostream>
#include <cstdlib>

using namespace std;
/* run this program using the console pauser or add your own getch,      system("pause") or input loop */


int main(int argc, char** argv) {

// Static Arrays    
char myChar[14] = {'H', 'e', 'l', 'l', 'o', ' ', 'F', 'r', 'i', 'e', 'n', 'd', '!', '\0'};

// Pointers

char *temp3 = myChar;

char *temp4 = newChar;

cout<<"\n\nThis is the original element for the char array.\n\n";
cout<<"\t";
for(int i = 0; i < 13; i++)
{
    cout<<"["<<*temp3<<"] ";
    temp3++;
}


    temp3 = myChar;
    cout<<"\n\nThis prints out every other character in the char array.\n\n";
    cout<<"\t";
    for(int i = 0; i < 13/2; i++)
    {
        temp3++;
        cout<<"["<<*temp3<<"] ";
        temp3++;
    }


// Attempt at splitting it by the first six digits
temp3 = myChar;
cout<<"\n\nThis prints out every other character in the char array.\n\n";
cout<<"\t";
for(int i = 0; i < 6; i++)
{

}


return 0;}