Question

我现在已经收到这个updateRoot: anHtmlRoot super updateRoot: anHtmlRoot. anHtmlRoot meta name: 'viewport'; content: 'width=device-width, initial-scale=1.0'错误2天了，我无法理解为什么会这样做。错误指向我解析的特定查询。但是为了测试它是我的代码还是只是一个错误，我将这个EXACT块从Parse的查询文档复制到我的项目中作为函数：

Command failed due to signal: Segmentation fault: 11

它再次向该块发送错误.. Xcode也将此消息抛给我的编译器：

为什么会这样？

更新

所以看来凯文的答案通过让编译器告诉我类型而不是在var query = PFQuery(className:"GameScore") query.whereKey("playerName", equalTo:"Sean Plott") query.findObjectsInBackgroundWithBlock { (objects: [AnyObject]?, error: NSError?) -> Void in if error == nil { // The find succeeded. println("Successfully retrieved \(objects!.count) scores.") // Do something with the found objects if let objects = objects as? [PFObject] { for object in objects { println(object.objectId) } } } else { // Log details of the failure println("Error: \(error!) \(error!.userInfo!)") } }行中指定它来清除编译器错误，将其更正为：

query.findObjectsInBackgroundWithBlock { (objects: [AnyObject]?, error: NSError?) -> Void in

但是这个其他块有点复杂，如何调整它以消除错误？：

query.findObjectsInBackgroundWithBlock {
    (objects, error) -> Void in
}

Answer 1

objects实际上属于[PFObject]?类型而不是[AnyObject]?。一个疯狂的猜测会说根本原因试图向下倾斜。

无论如何，只需使用正确的类型来修复此

query.findObjectsInBackgroundWithBlock {
    (objects: [PFObject]?, error: NSError?) -> Void in
}

或者让编译器告诉你类型

query.findObjectsInBackgroundWithBlock {
    (objects, error) -> Void in
}

Answer 2

        let query = PFQuery(className:"GameScore")

        query.whereKey("playerName", equalTo:"Sean Plott")

        query.findObjectsInBackgroundWithBlock {

            (objects:[AnyObject]?, error:NSError?) -> Void in

            if error == nil {

                // The find succeeded.

                print("Successfully retrieved \(objects!.count) scores.")

                // Do something with the found objects

                print(objects)

                if let objects = objects {

                    for object in objects {

                        print(object.objectId)

                    }

                }

            } else {

                // Log details of the failure

                print("Error: \(error!) \(error!.userInfo)")

            }

        }

试试这个！它有效！

此错误是Xcode 7还是swift 2中的错误？

2 个答案: