Question

请问您能帮我解决这个SQL问题吗？

SELECT * 
FROM
    (SELECT  
         SERIAL,ID,NAME,
         ROW_NUMBER() OVER (ORDER BY Date_Time) AS NUM1 
     FROM TABLE_1) AS X
FULL OUTER JOIN 
    (SELECT 
         PROGRAM, COLOR, PART, 
         ROW_NUMBER() OVER (ORDER BY Date_Time) AS NUM2 
     FROM TABLE_2) AS Y ON X.NUM1 = Y.NUM2

，输出

Serial  ID#  Name  Num1 Program     Color     part   Num2
---------------------------------------------------------
105057  8    A1     1   Basketball  Blue      12      1
104552  9    B2     2   Soccer      Yellow    15      2
104552  9    B2     3   Soccer      Yellow    15      3
104956  9    B2     4   Soccer      Yellow    15      4 
104956  8    A1     5   Basketball  Blue      12      5

如何根据完整联接计算和分组它们。我的输出应该是;

Serial  ID#  Name   Program     Color     part   Total
------------------------------------------------------
105057  8    A1     Basketball  Blue       12      2 
104552  9    B2     Soccer      Yellow     15      3

Answer 1

您需要select列，然后group by所有列。

SELECT
min(x.serial), x.id, x.name,
y.program, y.color, y.part, count(*) as total
FROM
(SELECT  SERIAL,ID,NAME,
ROW_NUMBER() OVER (ORDER BY Date_Time) AS NUM1 FROM TABLE_1) AS X
FULL OUTER JOIN 
(SELECT PROGRAM,COLOR,PART, 
ROW_NUMBER() OVER (ORDER BY Date_Time) AS NUM2 FROM TABLE_2) AS Y
ON X.NUM1 = Y.NUM2 
group by x.id, x.name, x.num1,
y.program, y.color, y.part, y.num2

Answer 2

您需要对重复的列进行分组，并使用函数选择Serial并获取Total。

SELECT MAX(Serial) as Serial, ID, Name, Program, Color, Part, COUNT(*) as Total
FROM
(SELECT SERIAL, ID, NAME,
  ROW_NUMBER() OVER (ORDER BY Date_Time) AS NUM1 FROM TABLE_1) AS X
FULL OUTER JOIN 
(SELECT PROGRAM,COLOR,PART, 
  ROW_NUMBER() OVER (ORDER BY Date_Time) AS NUM2 FROM TABLE_2) AS Y
ON X.NUM1 = Y.NUM2
GROUP BY ID, Name, Program, Color, Part

带有count和group的sql join

2 个答案: