Question

我有两张桌子

一个是

Receivesms（Matchdate，匹配时间，关键词，SmsMessage，Mobileno）

另一个是

QAoptios（关键字，问题，Answeroption，Matchdate，匹配时间）

我需要在同一SmsMessage，Answeroption和同一Matchdate上找到Matchtime的值与Keyword相同的值。而且我需要过滤Receivesms.Matchdate ='2012-12-25 00：00：00.000'

Answer 1

SELECT 
  q.AnswerOption,
  COUNT(SmsMessage) TheCount
FROM Receivesms r
INNER JOIN QAoptions q  ON r.Matchdate = q.Matchdate
                       AND r.Matchtime = q.Matchtime
                       AND r.Keyword = q.keyword
GROUP BY q.AnswerOption;

Answer 2

试试这个

SELECT count(*) from Receivesms as a  inner join QAoptios as b on a.keyword=b.keyword
and a.matchtime=b.matchtime and a.matchdate=b.matchdate and a.value=b.answeroption

Answer 3

使用可以使用：

    select count(*) from Recievesms r,QAoptios q 
    where
    r.Matchdate = q.Matchdate 
    and
    r.Matchtime = q.Matchtime
    and
    r. Keyword =q.Keyword
    and
    r.SmsMessage = q.Answeroption;

或

    select count(*) from from Recievesms as r
    inner join
    QAoptios as q 
    on  
    r.SmsMessage =   q.Answeroption;

Answer 4

SELECT COUNT(R.SmsMessage)
FROM Receivesms R
INNER JOIN QAoptios Q ON 
R.Keyword=Q.Keyword AND
R.Matchdate=Q.Matchdate AND
R.Matchtime=Q.Matchtime AND
R.SmsMessage=Q.AnswerOption

或者，如果要显示AnswerQuestion，可以添加GROUP BY子句，如下所示：

SELECT Q.AnswerOption, COUNT(R.SmsMessage) as TheCount
FROM Receivesms R
INNER JOIN QAoptios Q ON 
R.Keyword=Q.Keyword AND
R.Matchdate=Q.Matchdate AND
R.Matchtime=Q.Matchtime AND
R.SmsMessage=Q.AnswerOption
GROUP BY Q.AnswerOption

SQl通过计数组加入

4 个答案: