Question

我要求输入（X）并打印1 - 1000.X用于打印每行的X量。我如何实现这一目标？

perLine = int(input("How many numbers per line would you like: "))

for lineVariable in range(1, 1000, 1):
   print(lineVariable)

示例输出（5）

1 2 3 4 5
6 7 8 9 10
11 12 13 14 15

Answer 1

perLine = int(input("How many numbers per line would you like: "))


rn = map(str, range(1, 1000, 1))
from itertools import islice

print("\n".join([" ".join(islice(rn, perLine))
      for _ in range(1, 1000, perLine)]).rstrip())

Answer 2

以下是您的要求：

per_line = int(input("How many numbers per line would you like: "))

for number in range(1, 1001):
    print(number, end = " " if number % per_line else "\n")

给你以下输出：

How many numbers per line would you like: 10
1 2 3 4 5 6 7 8 9 10
11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30
31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50
.
.
981 982 983 984 985 986 987 988 989 990
991 992 993 994 995 996 997 998 999 1000

或者对于使用Python的grouper recipe

的版本

per_line = int(input("How many numbers per line would you like: "))

for line in zip(*[iter(range(1, 1001))] * per_line):
    print(" ".join([str(x) for x in line]))

Answer 3

仅在＆＃34; lineVariable＆＃34;时插入换行符是X的倍数：

perLine = int(input("How many numbers per line would you like: "))

for lineVariable in range(1, 1001):
   print(lineVariable, end=" ")
   if lineVariable%perLine==0:
        print("")

请注意，即使从1开始而不是0，如果要打印1000个值，则必须使用范围（1,1001）。

Answer 4

perLine = int(input("How many numbers per line would you like: "))

for lineVariable in range(1, 1000, 1):
   print(lineVariable * perLine)

Python 3.4.3 - 每行打印多个int

4 个答案: