Question

我编写了一个从用户那里获取文本文件的程序。

然后它应该一次打印60个字符然后从新行开始，但是，即使它可以正常工作

某些单词超过此限制然后将单词缩减为一半然后开始

再次在新线上。所以我需要我的程序基本上弄明白

该单词是否符合60个字符的限制，因此不会分割单词。

#include <stdio.h>
#include <stdlib.h>
int main( void )
{
char ch, file_name[25];
FILE *fp;
printf("Enter file name: \n");
scanf("%24s" ,file_name);

if ( (fp = fopen(file_name,"r")) == NULL ){
     perror("This file does not exist\n");
     exit(EXIT_FAILURE);}

int c, count;

count = 0;
while ( (c = fgetc(fp)) != EOF ) {
    if ( c == '\n' )
        putchar( ' ' );
    else
        putchar( c );

    count++;
    if ( count == 60 ) {
        putchar( '\n' );
        count = 0;
    }
}
putchar( '\n' );
fclose(fp);
}

Answer 1

#include <stdio.h>
#include <stdlib.h>
int readWord(FILE *fp,char *buff,char *lastChar){
    char c;
    int n=-1;
    *buff=0;
    *lastChar=0;
    while((c= fgetc(fp))!=EOF){
        n++;
        if(isspace(c)){
            /*
                you may keep tabs or replace them with spaces
            */
            *lastChar=c;
            break;
        }       
        buff[n]=c;
        buff[n+1]=0;
    }
    return n;
}


int main( void ) {
    char ch, file_name[25];
    char buff[50];
    int pos=0;
    FILE *fp;
    printf("Enter file name: \n");
    gets(file_name);

    if ( !(fp = fopen(file_name,"r")) ) {
        perror("This file does not exist\n");
        exit(EXIT_FAILURE);
    }

    int c, count;

    count = 0;
    while ( (pos=readWord(fp,buff,&ch))!=EOF) {
        count+=pos+(!!ch);
        if(count>60){
            printf("\n");
            count=pos;
        }

        if(ch){
            printf("%s%c",buff,ch);
        }else{
            printf("%s",buff);
        }
        if(!pos){
            count=0;
        }

    }
    putchar( '\n' );
    fclose(fp);
    return 0;
}

Answer 2

您可以扫描一个单词，如果行和单词小于60，则连接它们。否则，打印该行并将该单词复制到开始重复处理的行。

#include <stdio.h>
#include <string.h>

int main(void) {
    FILE *fp = NULL;
    char file_name[257] = {'\0'};
    char line[61] = {'\0'};
    char word[61] = {'\0'};
    int out = 0;

    printf ( "Enter file name:\n");
    scanf ( " %256[^\n]", file_name);

    if ( ( fp = fopen ( file_name, "r")) == NULL) {
        printf ( "could not open file\n");
        return 1;
    }

    while ( ( fscanf ( fp, "%60s", word)) == 1) {
        if ( strlen ( line) + strlen ( word) + 1 <= 60) {
            strcat ( line, " ");
            strcat ( line, word);
            out = 0;
        }
        else {
            printf ( "%s\n", line);
            strcpy ( line, word);
            out = 1;
        }
    }
    if ( !out) {
        printf ( "%s\n", line);
    }

    fclose ( fp);
    return 0;
}

每行打印60个字符

2 个答案: