Question

我得到了一张名为“宠物”的桌子。具有以下值

id | name | nickname | dateofborn |
1  | test | jhon     | 2009       |
2  | test2| test     | 2010       |
3  | mike | NULL     | 2010       |
3  | jhon | testor   | 2011       |

我想选择包含＆＃39; test＆＃39;的所有列。在name列或nickname列中的值，所以我有这个查询实际上不适合我：

SELECT * FROM pet WHERE name='test' OR nickname= 'test'

请注意，我确实希望测试值不是测试者。

Answer 1

查询是对的，我认为你的表有些问题。

但请尝试如下：

USE [yourDB es: animals];

SELECT * FROM [yourDB].pet WHERE (name='test' OR nickname='test');

Answer 2

试试这个。

fn<-function(x){ 
  s<-seq(from = as.POSIXct(x$start), 
         to = as.POSIXct(x$end)-1,by = "mins")
# here s is a sequence of all minutes in the given interval
  df<-data.table(x$id,x$cat,s)

# return new data.table that contains each calendar minute for each id 
# and categoryy of the original data
  df
}
# run the function above for each row in the data.table
dd<-adply(dt,1,fn)

# extract the date from calendar minutes
dd[,day:=format(as.POSIXct(s,"%d.%m.%Y %H:%M%:%S"), "%d.%m.%Y")]

#calculate sum of all minutes of event for each day, id and category
dd[,.N,by=c("day","id","cat")][order(day,id,cat)]

检查mysql中的任何一列是否有值

2 个答案: