Question

使用我的代码，我得到10以下数字的正确总和，但是当我的数字低于1000时，它似乎不正确。我不明白为什么简单地将10改为1000会导致我无法得到正确的解决方案。我得到了266333。

def multiplesofthreeandfive(number1, number2)
total1 = 0
total2 = 0

for i in 1..999

    if i % number1 == 0
        #puts "#{i}"
        total1 = total1 + i
    else
        #nothing
    end
end
for i in 1..999
#puts "#{i}"
    if i % number2 == 0
        #puts "#{i}"
        total2 = total2 + i
    else
        #nothing
    end
end
total3 = total1 + total2
puts "The 3 total is #{total1}"
puts "The 5 total is #{total2}"
puts "added together #{total3}"
end

puts multiplesofthreeandfive(3, 5)

Answer 1

谢谢minitech。我没有正确地思考这个问题。我改变了我的代码，它运作了！

def multiplesofthreeandfive(number1, number2)
total1 = 0
total2 = 0

for i in 1..999

    if i % number1 == 0 || i % number2 == 0
        #puts "#{i}"
        total1 = total1 + i
    else
        #nothing
    end
end
total3 = total1 + total2
puts "The 3 total is #{total1}"
end

puts multiplesofthreeandfive(3, 5)

项目Euler Q1 Ruby

1 个答案: