rm -f不会处理bash脚本中的所有参数

Question

在bash中有一个特殊的问题。我想创建一个脚本，该脚本采用文件名的前缀，并删除以该前缀开头并以某些给定后缀结尾的所有文件。为此，我有以下代码行：

#!/bin/bash

if [ $# -lt 1 ]; then
        echo "Please provide an argument";
        exit 1
fi

# Ending dot already included in $1
rm -f $1"aux" $1"bbl" $1"blg" $1"synctex.gz" $1"log"

# But even if you call it wrong...
rm -f $1".aux" $1".bbl" $1".blg" $1".synctex.gz" $1 ".log"

exit 0

不幸的是，当我按照预期调用我的脚本（名为cleanlatex）时：

cmd$ cleanlatex lpa_aaai.

仅删除.aux文件。很明显rm -f并没有将其应用扩展到所有参数，如果我明确地运行rm -f lpa_aaai.aux lpa_aaai.bbl ...，这就是我要做的事情。我在这里做错了什么？

编辑：要回答@ Etan的问题，这是我在添加这些命令时看到的内容：

+ '[' 1 -lt 1 ']'
+ rm -v lpa_aaai.aux lpa_aaai.bbl lpa_aaai.blg lpa_aaai.synctex.gz lpa_aaai.log
removed ‘lpa_aaai.aux’
removed ‘lpa_aaai.bbl’
removed ‘lpa_aaai.blg’
removed ‘lpa_aaai.synctex.gz’
removed ‘lpa_aaai.log’
+ rm -v lpa_aaai..aux lpa_aaai..bbl lpa_aaai..blg lpa_aaai..synctex.gz lpa_aaai. .log
rm: cannot remove ‘lpa_aaai..aux’: No such file or directory
rm: cannot remove ‘lpa_aaai..bbl’: No such file or directory
rm: cannot remove ‘lpa_aaai..blg’: No such file or directory
rm: cannot remove ‘lpa_aaai..synctex.gz’: No such file or directory
rm: cannot remove ‘lpa_aaai.’: No such file or directory
rm: cannot remove ‘.log’: No such file or directory

第二组由cannot remove消息组成，与我无关：我只将这些删除视为故障保护。这完全符合我的需要。谢谢。