Question

好的，这是我的问题

我在gridview中显示2个相关列两个来自同一个外国表我显示名字和姓氏作为全名并通过电子邮件发送另一栏所有这3个数据来自同一个表

 'columns' => [
        ['class' => 'yii\grid\CheckboxColumn'],
        [

            'attribute' => 'event_id',
            'label' => 'Event Title',
            'value' => 'event.title'
        ],
        [
            'attribute' => 'user_id',
            'label' => 'Name',
            'value' => 'users.fullname',
        ],
        [
            'attribute' => 'user_id',
            'label' => 'Email',
            'value' => 'users.email',
        ],

如你所知，如果我想让它可以搜索，我必须将属性设为user_id 这是我的search模型

$query->joinWith(['event', 'users']);
$query->andFilterWhere(['like', 'event.title', $this->event_id]);
    $query->andFilterWhere(['like', 'user.firstname', $this->user_id]);
    $query->andFilterWhere(['like', 'user.email', $this->user_id]);

现在问题是搜索电子邮件的工作正常我的意思是当我在电子邮件列的搜索框中输入任何数据时，它会user_id罚款，但它会自动创建where email=blah blah AND firstname=blah blah之类的查询事实上，我还没有在fullname列搜索框中输入任何数据

当我在fullname列搜索中输入任何数据时，它不会找到该表的user_id

我该如何解决这个冲突？哦，我的数据库结构是这样的此gridview是checkin表，其中我显示签入特定事件的所有用户所以还有2个表event和users

 CREATE TABLE IF NOT EXISTS `event` (
  `id` int(11) NOT NULL,
  `organiser_id` int(11) NOT NULL,
  `interest_id` int(11) NOT NULL,
  `title` varchar(255) NOT NULL,
  `description` varchar(500) NOT NULL,
  `location` varchar(255) NOT NULL,
  `is_active` bit(1) NOT NULL,

) 

 CREATE TABLE IF NOT EXISTS `user` (
  `id` int(11) NOT NULL,
  `firstname` varchar(255) DEFAULT NULL,
  `lastname` varchar(255) DEFAULT NULL,
  `dob` datetime DEFAULT NULL,
  `email` varchar(100) DEFAULT NULL,
  `username` varchar(100) DEFAULT NULL,
  `password` varchar(100) DEFAULT NULL,
  `area_intrest` varchar(250) NOT NULL,
)

CREATE TABLE IF NOT EXISTS `checkin` (
  `id` int(11) NOT NULL,
  `user_id` int(11) NOT NULL,
  `event_id` int(11) NOT NULL,
  `user_type` enum('competitor','fan') NOT NULL,
)

这是我的搜索功能代码

class CheckinSearch extends Checkin

{

public $fullName;
/**
 * @inheritdoc
 */
public function rules()
{
    return [
        [['id', 'created_by', 'updated_by'], 'integer'],
        [['user_type', 'user_id', 'event_id', 'created_date', 'updated_date','fullName'], 'safe'],
    ];
}

/**
 * @inheritdoc
 */
public function scenarios()
{
    // bypass scenarios() implementation in the parent class
    return Model::scenarios();
}

/**
 * Creates data provider instance with search query applied
 *
 * @param array $params
 *
 * @return ActiveDataProvider
 */
public function search($params)
{

    if(!isset($_GET['id'])){
        $id='';
    }
    else{
        $id=$_GET['id'];
    }

    $query = Checkin::find()->where(['event_id'=> $id]);

    $query->joinWith(['event', 'users']);


    $dataProvider = new ActiveDataProvider([
        'query' => $query,
    ]);

    $this->load($params);

    if (!$this->validate()) {
        // uncomment the following line if you do not want to return any records when validation fails
        // $query->where('0=1');
        return $dataProvider;
    }

    $query->andFilterWhere([
        'id' => $this->id,
        'created_date' => $this->created_date,
        'created_by' => $this->created_by,
        'updated_date' => $this->updated_date,
        'updated_by' => $this->updated_by,
    ]);

    $query->andFilterWhere(['like', 'event.title', $this->event_id]);
    $query->andFilterWhere(['like', 'user.firstname', $this->fullName]);
    $query->andFilterWhere(['like', 'user.lastname', $this->fullName]);
    $query->andFilterWhere(['like', 'user.email', $this->user_id]);
    $query->andFilterWhere(['like', 'user_type', $this->user_type]);

    return $dataProvider;
    }
}

如果我添加了firstname和lastname过滤器，它会生成像这样的查询

   SELECT COUNT(*) FROM `checkin` LEFT JOIN `event` ON `checkin`.`event_id` = `event`.`id` 
LEFT JOIN `user` ON `checkin`.`user_id` = `user`.`id` WHERE 
((`event_id`='11') AND (`user`.`firstname` LIKE '%text%')) AND 
(`user`.`lastname` LIKE '%text%')

我想使用AND或OR过滤器

生成这样的查询

SELECT * FROM `checkin` LEFT JOIN `event` ON `checkin`.`event_id` = `event`.`id` 
LEFT JOIN `user` ON `checkin`.`user_id` = `user`.`id` WHERE 
((`event_id`='11') AND (`user`.`firstname` LIKE '%text%')) OR 
((`event_id`='11') AND (`user`.`lastname` LIKE '%text%'))

谢谢

Answer 1

谢谢你的帮助但我遇到了关于stackoverflow的问题并解决了它这就是我做的事情

$query->andFilterWhere(['or',
        ['like','user.firstname',$this->fullName],
        ['like','user.lastname',$this->fullName]]);

此查询将同时显示firstname或lastname 似乎现在解决了我的问题

Answer 2

在模型中为full_name创建另一个变量，将该变量添加到安全搜索＆amp;使用该变量进行搜索＆amp;同时显示全名。

假设您的新变量是＆＃34; full_name＆＃34;

然后在搜索功能中添加以下行

$query->andFilterWhere(['like', 'user.firstname', $this->full_name]);

在视图中

[
    'attribute' => 'full_name',
    'label' => 'Name',
    'value' => 'users.fullname',
],

与相关数据搜索中的ID冲突yii2

2 个答案: