Question

首先，我知道这里有一个类似的问题：Filter setup for related model in GridView。我试图遵循这一点，但这并没有成功。

我还检查了不同的指南，但我仍然卡住了。作为参考，我在这里遵循这些指南

但是，我的视图中仍然没有搜索字段+排序功能。

我使用 gii 来创建CRUD功能。

My Manufacturers.php（型号）：

// basic model, nothing special here. 
// The following line was added to create a relation
public function getVendor()
{
    return $this->hasOne(Vendors::className(), ['vendor_id' =>   'vendor_id']);
}

我的制造商SearchSearch.php（型号）：

namespace app\models;

use Yii;
use yii\base\Model;
use yii\data\ActiveDataProvider;
use app\models\Manufacturers;

/**
 * ManufacturersSearch represents the model behind the search form about `app\models\Manufacturers`.
 */
class ManufacturersSearch extends Manufacturers
{
    public $vendor;
    /**
     * @inheritdoc
     */
    public function rules()
    {
        return [
            [['manufacturer_id', 'vendor_id'], 'integer'],
            [['name', 'vendor'], 'safe'],
        ];
    }

    /**
     * @inheritdoc
     */
    public function scenarios()
    {
        // bypass scenarios() implementation in the parent class
        return Model::scenarios();
    }

    /**
     * Creates data provider instance with search query applied
     *
     * @param array $params
     *
     * @return ActiveDataProvider
     */
    public function search($params)
    {
        $query = Manufacturers::find();
        $query->joinWith("vendor");

        // add conditions that should always apply here

        $dataProvider = new ActiveDataProvider([
            'query' => $query,
        ]);

        $dataProvider->sort->attributes['vendor_name'] = [
            // The tables are the ones our relation are configured to
            // in my case they are prefixed with "tbl_"
            'asc' => ['vendor.name' => SORT_ASC],
            'desc' => ['vendor.name' => SORT_DESC],
        ];

        if (!$this->load($params) && $this->validate()) {
            // uncomment the following line if you do not want to return any records when validation fails
            // $query->where('0=1');
            return $dataProvider;
        }

        // grid filtering conditions
        $query->andFilterWhere([
            'manufacturer_id' => $this->manufacturer_id,
            'vendor_id' => $this->vendor_id,
        ]);

        $query->andFilterWhere(['like', 'name', $this->name]);
        $query->andFilterWhere(['like', 'vendor.vendor', $this->vendor]);
        return $dataProvider;
    }
}

最后是我的观看文件：

<?php Pjax::begin(); ?>    <?= GridView::widget([
    'dataProvider' => $dataProvider,
    'filterModel' => $searchModel,
    'columns' => [
        ['class' => 'yii\grid\SerialColumn'],
        'name',
        [
            'label' => 'Hauptlieferant',
            'value' => 'vendor.name',
        ],
        ['class' => 'yii\grid\ActionColumn'],
    ],
]); ?>
<?php Pjax::end(); ?></div>

这是我目前的输出：

所以，它有点工作，因为而不是ID，我得到了名字（这是我想要的）。但由于某些原因，这些字段不可排序也不可搜索。

表“制造商”以及表“供应商”有一列“名称”

感谢任何正确方向的提示。

Answer 1

在ManufactuiresSearch中，您还需要加入过滤器

    $query->andFilterWhere(['like', 'name', $this->name]);

    $query->joinWith(['vendor' => function ($q) {
        $q->andFilterWhere(['like', 'vendor.vendor', $this->vendor]);
    }]);

    return $dataProvider;

在GridView中搜索+排序相关模型（yii2）

1 个答案: