Question

首次使用tkinter在Python中编码;在线搜索和手册没有用（对我而言）。

以下是此问题的示例：

（我会放一张图片，但是我的声望很低，所以我不能这样做。）

我有一个定义，它加载名为Load_Main_Menu的系统的其他部分。您可以从这里进入食物菜单，饮料菜单等。为了便于使用，我对其进行了编辑，这样您就不必编写代码来使其工作。

我有一个显示主菜单的定义，用户可以用来进入系统其他部分的按钮。我已经减少了我已有的代码，因此您可以复制并粘贴它，看看我的意思：

import tkinter#Imports Tkinter. Used for the user interface.
from tkinter import *#Imports the package tkinter for the user interface.
from tkinter import ttk#Imports the ttk module, used in the Food/Drink menus.

root = Tk()

tree = ttk.Treeview(root)

def Load_Main_Menu():#Loads the main menu (Food, Drink, Exit, etc.)
#Positions the buttons by setting topFrame as the top (re:First), bottomFrame as
#bottom (re: Last) and then the other buttons fill the space between
Top_Frame = Frame(root)
Top_Frame.pack()
Bottom_Frame = Frame(root)
Bottom_Frame.pack(side = BOTTOM)

#This chunk of code creates the buttons, sets the text, links it to the
#function and also decides it's colour.
Menu_Food_Button = Button(Top_Frame, text = "Food", command = Food_Button, fg = 'Blue')
Menu_Stock_Button = Button(Top_Frame, text = "Stock Control", command = Stock_Control_Button, fg = 'Green')

#The code below determines which side of the parent widget packs against.
Menu_Food_Button.pack(side=LEFT)
Menu_Stock_Button.pack(side=LEFT)

root.mainloop()

def Food_Menu():  
tree['columns'] = ('Price', 'Qty', 'Print Receipt')#additional columns after the default '#0'

tree.column('Price', stretch = 0, width = 100, anchor = E)#Price Column, tkinter.E aligns contents to the "east"
tree.column('Qty', stretch = 0, width = 100, anchor = E)#Quantity Column
tree.column('Print Receipt', stretch = 0, width = 100, anchor = E)#Print Receipt Column
tree.heading('#0', text = "Item")# default column responsible for tree mechanics
tree.heading('Price', text = "£")
tree.heading('Qty', text = "Quantity")
tree.heading('Print Receipt', text = "Get Receipt")

tree.insert('', 0, 'Print_Receipt', text = "Get Receipt")#

tree.insert('', 0, '_Chips_', text = "Chips", values = (4.99, 133))#Parent, text goes to '#0', values go to tree['columns']
tree.insert('_Chips_', 0, text = "Add to Order")#Child

tree.pack()
root.mainloop()

def Stock_Menu():#Loads the main menu (Food, Drink, Exit, etc.)
#Positions the buttons by setting topFrame as the top (re:First), bottomFrame as
#bottom (re: Last) and then the other buttons fill the space between
Top_Frame = Frame(root)
Top_Frame.pack()
Bottom_Frame = Frame(root)
Bottom_Frame.pack(side = BOTTOM)

#This chunk of code creates the buttons, sets the text, links it to the
#function and also decides it's colour.
Stock_Exit_Button = Button(Top_Frame, text = "Exit", command = Return_To_Main_Menu, fg = 'Green')

#The code below determines which side of the parent widget packs against.
Stock_Exit_Button.pack(side=LEFT)

root.mainloop()

def Food_Button():#This displays the food menu.
Food_Menu()

def Stock_Control_Button():#This displays the stock options
Stock_Menu()

def Return_To_Main_Menu():#Loads the main menu
Load_Main_Menu()

Load_Main_Menu()

所以，如果你有C＆amp; P，你会看到一个窗口出现两个按钮，食物和股票。

点击食物，

点击股票，

单击退出，

点击股票，

单击“退出”。

你应该看到这个问题。我希望能够关闭窗户＆＃39;在我身后＆＃39;所以他们不会堆积，因为它是一种需要修复的错误，但我不知道如何。

我已经在网上看过了，正如我所说的那样，并且没有任何结果。

Answer 1

我通过其他答案修复了缩进和root.mainloop（）建议。如果您不再需要显示树，则可以使用tree.destroy()。但是，我认为在这种情况下使用tree.pack_forget()更合适，如此答案here所示。

我已将tree.pack_forget()添加到您的Return_To_Main_Menu()功能并删除了原来的Load_Main_Menu()来电，因为它会创建两个新的食物和股票按钮..我删除了原始帖子中的评论为了更容易发布。

import tkinter
from tkinter import *
from tkinter import ttk

root = Tk()

tree = ttk.Treeview(root)

def Load_Main_Menu():
    Top_Frame = Frame(root)
    Top_Frame.pack()
    Bottom_Frame = Frame(root)
    Bottom_Frame.pack(side = BOTTOM)

    Menu_Food_Button = Button(Top_Frame, text = "Food", command = Food_Button, fg = 'Blue')
    Menu_Stock_Button = Button(Top_Frame, text = "Stock Control", command = Stock_Control_Button, fg = 'Green')

    Menu_Food_Button.pack(side=LEFT)
    Menu_Stock_Button.pack(side=LEFT)

    root.mainloop()

def Food_Menu():  
    tree['columns'] = ('Price', 'Qty', 'Print Receipt')

    tree.column('Price', stretch = 0, width = 100, anchor = E)
    tree.column('Qty', stretch = 0, width = 100, anchor = E)
    tree.column('Print Receipt', stretch = 0, width = 100, anchor = E)
    tree.heading('#0', text = "Item")
    tree.heading('Price', text = "£")
    tree.heading('Qty', text = "Quantity")
    tree.heading('Print Receipt', text = "Get Receipt")

    tree.insert('', 0, 'Print_Receipt', text = "Get Receipt")

    tree.insert('', 0, '_Chips_', text = "Chips", values = (4.99, 133))
    tree.insert('_Chips_', 0, text = "Add to Order")#Child

    tree.pack()

def Stock_Menu():
    Top_Frame = Frame(root)
    Top_Frame.pack()
    Bottom_Frame = Frame(root)
    Bottom_Frame.pack(side = BOTTOM)

    Stock_Exit_Button = Button(Top_Frame, text = "Exit", command = Return_To_Main_Menu, fg = 'Green')

    Stock_Exit_Button.pack(side=LEFT)


def Food_Button():
    Food_Menu()

def Stock_Control_Button():
    Stock_Menu()

def Return_To_Main_Menu():
    tree.pack_forget()

Load_Main_Menu()

如何在Python 3.4.3中关闭tkinter中的窗口？

1 个答案: