以下是我在自引用表 emp_tabref1
上执行的函数 get_reporteesCREATE OR REPLACE FUNCTION get_reportees4(IN id integer)
RETURNS TABLE(e_id integer, e_name character varying, e_manager integer, e_man_name character varying) AS
$$
BEGIN
RETURN QUERY
WITH RECURSIVE manger_hierarchy(e_id, e_name, m_id, m_name) AS
(
SELECT e.emp_id, e.emp_name, e.mgr_id, e.emp_name AS man_name
FROM emp_tabref1 e WHERE e.emp_id = id
UNION
SELECT rp.emp_id, rp.emp_name, rp.mgr_id, rp.emp_name AS man_name
FROM manger_hierarchy mh INNER JOIN emp_tabref1 rp ON mh.e_id = rp.mgr_id
)
SELECT * from manger_hierarchy;
END;
$$ LANGUAGE plpgsql VOLATILE
emp_tabref1的表结构:
CREATE TABLE **emp_tabref1**
(
emp_id integer NOT NULL,
emp_name character varying(50) NOT NULL,
mgr_id integer,
CONSTRAINT emp_tabref_pkey PRIMARY KEY (emp_id),
CONSTRAINT emp_tabref_mgr_id_fkey FOREIGN KEY (mgr_id)
REFERENCES emp_tabref (emp_id) MATCH SIMPLE
ON UPDATE NO ACTION ON DELETE NO ACTION
)
我想要返回的是我们传递的id的层次结构(上面和下面),它将包含emp_name,emp_id,mgr_id和 mgr_name 。
但我的功能是这样回来的:
select * from get_reportees4(9)
e_id e_name e_manager e_man_name
1 9 "Emp9" 10 "Emp9"
2 5 "Emp5" 9 "Emp5"
3 6 "Emp6" 9 "Emp6"
我的预期输出是
e_id e_name e_manager e_man_name
1 9 "Emp9" 10 "Emp10"
2 5 "Emp5" 9 "Emp9"
3 6 "Emp6" 9 "Emp9"
该函数应返回管理员名称而不是员工姓名。请帮忙!
答案 0 :(得分:0)
找到解决方案!通过使用mgr_id和emp_id
在临时manger_hierarchy表和emp_tabref1表之间创建新连接CREATE OR REPLACE FUNCTION get_reportees4(IN id integer)
RETURNS TABLE(e_id integer, e_name character varying, e_manager integer, e_man_name character varying) AS
$$
BEGIN
RETURN QUERY
WITH RECURSIVE manger_hierarchy(e_id, e_name, m_id, m_name) AS
(
SELECT e.emp_id, e.emp_name, e.mgr_id, e.emp_name AS man_name
FROM emp_tabref1 e WHERE e.emp_id = id
UNION
SELECT rp.emp_id, rp.emp_name, rp.mgr_id, rp.emp_name AS man_name
FROM manger_hierarchy mh INNER JOIN emp_tabref1 rp ON mh.e_id = rp.mgr_id
)
SELECT manger_hierarchy.e_id, manger_hierarchy.e_name, manger_hierarchy.m_id, emp_tabref1.emp_name
FROM manger_hierarchy LEFT JOIN emp_tabref1 ON manger_hierarchy.m_id = emp_tabref1.emp_id;
END;
$$ LANGUAGE plpgsql VOLATILE
SELECT manger_hierarchy.e_id,manger_hierarchy.e_name,manger_hierarchy.m_id,emp_tabref1.emp_name FROM manger_hierarchy LEFT JOIN emp_tabref1 ON manger_hierarchy.m_id = emp_tabref1.emp_id;