我有两张表,比如
表1:
c_id, p_id, sales
x, 1, 1
x, 2, 1
x, 3, 1
x, 4, 1
y, 5, 1
y, 4, 1
y, 3, 1
y, 6, 1
y, 7, 1
z, 1, 1
z, 8, 1
表2:
c_id, p_id, sales
x, 8, 1
x, 2, 1
x, 7, 1
y, 5, 1
y, 2, 1
y, 3, 1
z, 3, 1
我想得到表2中但不存在于table1中的c_id和p_id对。所以结果应该是这样的:
c_id p_id sales
x, 8, 1
x, 7, 1
y, 2, 1
z, 3, 1
我使用了以下代码,但它不起作用:
select b.c_id, b.p_id, b.sales
from table1 as a
join table2 as b
on a.c_id = b.c_id
where a.p_id != b.p_id
感谢
答案 0 :(得分:0)
您想使用left join
,然后检查不匹配:
select b.c_id, b.p_id, b.sales
from table2 b left join
table1 a
on a.c_id = b.c_id and a.p_id = b.p_id
where a.c_id is null;